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17:12:56",{"text":11,"minutes":126,"time":127,"words":128},2.1,126000,420,{"stem":130,"path":131,"title":132,"date":133,"collapsed":9,"readingTime":134},"posts\u002FUGCourses\u002F2.sophomore-autumn\u002FProbability-Theory","\u002F2025\u002F01\u002F21\u002FProbability-Theory","概率论与数理统计","2025-01-21 12:52:11",{"text":11,"minutes":135,"time":136,"words":137},2.205,132300,441,{"stem":139,"path":140,"title":141,"date":142,"collapsed":9,"readingTime":143},"posts\u002FUGCourses\u002F2.sophomore-autumn\u002Fengineering-training","\u002F2024\u002F09\u002F17\u002Fengineering-training","工程训练","2024-09-17 21:40:26",{"text":11,"minutes":144,"time":145,"words":146},2.385,143100,477,{"stem":148,"path":149,"title":150,"date":78,"collapsed":9,"readingTime":151},"posts\u002FUGCourses\u002F2.sophomore-autumn\u002Findex","\u002Fugcourses\u002Fsophomore-autumn","大二秋冬",{"text":80,"minutes":81,"time":81,"words":81},{"stem":153,"path":154,"title":155,"date":156,"collapsed":9,"readingTime":157},"posts\u002FUGCourses\u002F2.sophomore-autumn\u002Fsolid-state-physics","\u002F2024\u002F09\u002F11\u002Fsolid-state-physics","固体物理基础","2024-09-11 19:15:26",{"text":158,"minutes":159,"time":160,"words":161},"4 min read",3.21,192600,642,{"stem":163,"path":164,"title":165,"date":166,"collapsed":9,"readingTime":167},"posts\u002FUGCourses\u002F3.sophomore-spring\u002FAIFrontier","\u002Fugcourses\u002Fsophomore-spring\u002Faifrontier","人工智能前沿","2025-06-12 14:58:16",{"text":168,"minutes":169,"time":170,"words":171},"25 min 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19:39:00",{"text":60,"minutes":200,"time":201,"words":202},0.535,32100,107,{"stem":204,"path":205,"title":206,"date":207,"collapsed":9,"readingTime":208},"posts\u002FUGCourses\u002F4.junior-autumn\u002F1.microelectronic-devices\u002FLecture10","\u002Fugcourses\u002Fjunior-autumn\u002Fmicroelectronic-devices\u002Flecture10","Lecture 10：从 MOS 电容到 MOSFET","2026-09-10 00:10:00",{"text":209,"minutes":210,"time":211,"words":212},"18 min read",17.615,1056900,3523,{"stem":214,"path":215,"title":216,"date":217,"collapsed":9,"readingTime":218},"posts\u002FUGCourses\u002F4.junior-autumn\u002F1.microelectronic-devices\u002FLecture11","\u002Fugcourses\u002Fjunior-autumn\u002Fmicroelectronic-devices\u002Flecture11","Lecture 11：亚阈值效应与 MOSFET 尺寸缩放","2026-09-10 00:20:00",{"text":219,"minutes":220,"time":221,"words":222},"23 min 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00:50:00",{"text":21,"minutes":51,"time":52,"words":53},{"stem":340,"path":341,"title":342,"date":198,"collapsed":343,"readingTime":344},"posts\u002FUGCourses\u002F4.junior-autumn\u002F1.microelectronic-devices\u002Findex","\u002Fugcourses\u002Fjunior-autumn\u002Fmicroelectronic-devices","微电子器件",true,{"text":158,"minutes":345,"time":346,"words":347},3.055,183300,611,{"stem":349,"path":350,"title":351,"date":352,"collapsed":9,"readingTime":353},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F1.HistoryMetaCharacters","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fhistorymetacharacters","History & Meta Characters","2026-09-10 20:25:44",{"text":269,"minutes":354,"time":355,"words":356},9.36,561600,1872,{"stem":358,"path":359,"title":360,"date":361,"collapsed":9,"readingTime":362},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F10.PastExams\u002F1.ExamAutumn2223","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fpastexams\u002Fexamautumn2223","22-23 秋冬历年卷","2026-09-10 20:26:49",{"text":319,"minutes":363,"time":364,"words":365},20.295,1217700,4059,{"stem":367,"path":368,"title":369,"date":370,"collapsed":9,"readingTime":371},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F10.PastExams\u002F2.Exam2021","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fpastexams\u002Fexam2021","20-21 历年卷","2026-09-10 20:26:50",{"text":289,"minutes":290,"time":291,"words":292},{"stem":373,"path":374,"title":375,"date":376,"collapsed":9,"readingTime":377},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F10.PastExams\u002F3.ExamRecall1","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fpastexams\u002Fexamrecall1","不知名回忆卷 1","2026-09-10 20:26:51",{"text":116,"minutes":378,"time":379,"words":380},4.215,252900,843,{"stem":382,"path":383,"title":384,"date":385,"collapsed":9,"readingTime":386},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F10.PastExams\u002F4.ExamRecall23","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fpastexams\u002Fexamrecall23","不知名回忆卷 2\u002F3","2026-09-10 20:26:52",{"text":387,"minutes":388,"time":389,"words":390},"12 min read",11.235,674100,2247,{"stem":392,"path":393,"title":394,"date":395,"collapsed":9,"readingTime":396},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F11.Detailed\u002F1.Chapter1-Introduction","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fdetailed\u002Fchapter1-introduction","Chapter 1：Introduction","2026-09-10 20:27:26",{"text":397,"minutes":398,"time":399,"words":400},"19 min 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20:27:54",{"text":209,"minutes":454,"time":455,"words":456},17.85,1071000,3570,{"stem":458,"path":459,"title":460,"date":461,"collapsed":9,"readingTime":462},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F11.Detailed\u002F8.Chapter8-CProgrammingInUnix","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fdetailed\u002Fchapter8-cprogramminginunix","Chapter 8：C Programming in Unix","2026-09-10 20:27:57",{"text":463,"minutes":464,"time":465,"words":466},"17 min read",16.855,1011300,3371,{"stem":468,"path":469,"title":470,"date":471,"collapsed":9,"readingTime":472},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F2.LinuxUnix","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Flinuxunix","Linux & Unix","2026-09-10 20:25:46",{"text":41,"minutes":473,"time":474,"words":475},29.33,1759800,5866,{"stem":477,"path":478,"title":479,"date":480,"collapsed":9,"readingTime":481},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F3.Vi","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fvi","Vi","2026-09-10 20:25:47",{"text":329,"minutes":482,"time":483,"words":484},7.95,477000,1590,{"stem":486,"path":487,"title":488,"date":489,"collapsed":9,"readingTime":490},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F4.ViCopy","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fvicopy","Vi（详细版）","2026-09-10 20:25:49",{"text":279,"minutes":491,"time":492,"words":493},13.785,827100,2757,{"stem":495,"path":496,"title":497,"date":498,"collapsed":9,"readingTime":499},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F5.Shells","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fshells","Shells","2026-09-10 20:25:51",{"text":500,"minutes":501,"time":502,"words":503},"22 min read",21.21,1272600,4242,{"stem":505,"path":506,"title":507,"date":508,"collapsed":9,"readingTime":509},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F6.Network","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fnetwork","Network","2026-09-10 20:25:54",{"text":319,"minutes":510,"time":511,"words":512},20.595,1235700,4119,{"stem":514,"path":515,"title":516,"date":517,"collapsed":9,"readingTime":518},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F7.SystemAdministration","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fsystemadministration","System Administration","2026-09-10 20:26:44",{"text":329,"minutes":519,"time":520,"words":521},7.12,427200,1424,{"stem":523,"path":524,"title":525,"date":526,"collapsed":9,"readingTime":527},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F8.XWindow","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fxwindow","XWindow","2026-09-10 20:26:45",{"text":97,"minutes":528,"time":529,"words":530},5.105,306300,1021,{"stem":532,"path":533,"title":534,"date":535,"collapsed":9,"readingTime":536},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002F9.SystemDevelopmentTools","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad\u002Fsystemdevelopmenttools","System Development Tools","2026-09-10 20:26:47",{"text":387,"minutes":537,"time":538,"words":539},11.35,681000,2270,{"stem":541,"path":542,"title":543,"date":544,"collapsed":343,"readingTime":545},"posts\u002FUGCourses\u002F4.junior-autumn\u002F2.ICCAD\u002Findex","\u002Fugcourses\u002Fjunior-autumn\u002Ficcad","面向 ICCAD 的软件基础技术","2026-09-10 12:37:00",{"text":60,"minutes":546,"time":547,"words":548},0.185,11100,37,{"stem":550,"path":551,"title":552,"date":553,"collapsed":9,"readingTime":554},"posts\u002FUGCourses\u002F4.junior-autumn\u002F3.HDL\u002FFeiQilai1","\u002Fugcourses\u002Fjunior-autumn\u002Fhdl\u002Ffeiqilai1","飞起来1.0","2026-09-10 12:51:49",{"text":555,"minutes":556,"time":557,"words":558},"105 min read",104.655,6279300,20931,{"stem":560,"path":561,"title":562,"date":563,"collapsed":9,"readingTime":564},"posts\u002FUGCourses\u002F4.junior-autumn\u002F3.HDL\u002FFeiQilai2","\u002Fugcourses\u002Fjunior-autumn\u002Fhdl\u002Ffeiqilai2","飞起来2.0","2026-09-10 12:52:06",{"text":565,"minutes":566,"time":567,"words":568},"29 min read",28.755,1725300,5751,{"stem":570,"path":571,"title":572,"date":573,"collapsed":9,"readingTime":574},"posts\u002FUGCourses\u002F4.junior-autumn\u002F3.HDL\u002FFeiQilai3","\u002Fugcourses\u002Fjunior-autumn\u002Fhdl\u002Ffeiqilai3","飞起来3.0","2026-09-10 12:52:12",{"text":116,"minutes":575,"time":576,"words":577},4.49,269400,898,{"stem":579,"path":580,"title":581,"date":582,"collapsed":9,"readingTime":583},"posts\u002FUGCourses\u002F4.junior-autumn\u002F3.HDL\u002FLecture13","\u002Fugcourses\u002Fjunior-autumn\u002Fhdl\u002Flecture13","Lecture 13：浮点数标准","2026-09-10 12:51:27",{"text":11,"minutes":584,"time":585,"words":586},2.575,154500,515,{"stem":588,"path":589,"title":590,"date":591,"collapsed":9,"readingTime":592},"posts\u002FUGCourses\u002F4.junior-autumn\u002F3.HDL\u002FLecture6","\u002Fugcourses\u002Fjunior-autumn\u002Fhdl\u002Flecture6","Lecture 6：Behavioral Modeling，非阻塞赋值","2026-09-10 12:51:12",{"text":97,"minutes":593,"time":594,"words":595},5.34,320400,1068,{"stem":597,"path":598,"title":599,"date":600,"collapsed":9,"readingTime":601},"posts\u002FUGCourses\u002F4.junior-autumn\u002F3.HDL\u002FPPTCorrespondence","\u002Fugcourses\u002Fjunior-autumn\u002Fhdl\u002Fpptcorrespondence","与PPT的对应","2026-09-10 12:52:18",{"text":269,"minutes":602,"time":603,"words":604},9.275,556500,1855,{"stem":606,"path":607,"title":608,"date":544,"collapsed":343,"readingTime":609},"posts\u002FUGCourses\u002F4.junior-autumn\u002F3.HDL\u002Findex","\u002Fugcourses\u002Fjunior-autumn\u002Fhdl","硬件描述语言原理与应用",{"text":60,"minutes":61,"time":62,"words":63},{"stem":611,"path":612,"title":613,"date":614,"collapsed":9,"readingTime":615},"posts\u002FUGCourses\u002F4.junior-autumn\u002F4.analogICDesign\u002F1.BeforeMidterm","\u002Fugcourses\u002Fjunior-autumn\u002Fanalogicdesign\u002Fbeforemidterm","期中前","2026-09-10 20:28:52",{"text":616,"minutes":617,"time":618,"words":619},"11 min read",10.835,650100,2167,{"stem":621,"path":622,"title":623,"date":624,"collapsed":9,"readingTime":625},"posts\u002FUGCourses\u002F4.junior-autumn\u002F4.analogICDesign\u002F2.MidtermExam2425","\u002Fugcourses\u002Fjunior-autumn\u002Fanalogicdesign\u002Fmidtermexam2425","24-25 期中","2026-09-10 20:29:00",{"text":21,"minutes":626,"time":627,"words":628},1.22,73200,244,{"stem":630,"path":631,"title":632,"date":633,"collapsed":9,"readingTime":634},"posts\u002FUGCourses\u002F4.junior-autumn\u002F4.analogICDesign\u002F3.FinalExamReview","\u002Fugcourses\u002Fjunior-autumn\u002Fanalogicdesign\u002Ffinalexamreview","期末考试整理","2026-09-10 20:29:09",{"text":387,"minutes":635,"time":636,"words":637},11.36,681600,2272,{"stem":639,"path":640,"title":641,"date":642,"collapsed":343,"readingTime":643},"posts\u002FUGCourses\u002F4.junior-autumn\u002F4.analogICDesign\u002Findex","\u002Fugcourses\u002Fjunior-autumn\u002Fanalogicdesign","模拟集成电路设计","2026-09-10 20:00:00",{"text":80,"minutes":81,"time":81,"words":81},{"stem":645,"path":646,"title":647,"date":78,"collapsed":9,"readingTime":648},"posts\u002FUGCourses\u002F4.junior-autumn\u002Findex","\u002Fugcourses\u002Fjunior-autumn","大三秋冬",{"text":80,"minutes":81,"time":81,"words":81},{"stem":650,"path":651,"title":652,"date":653,"collapsed":9,"readingTime":654},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F1.Chapter3-Device","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fchapter3-device","Chapter 3：器件 Device","2026-09-10 21:14:41",{"text":249,"minutes":655,"time":656,"words":657},6.055,363300,1211,{"stem":659,"path":660,"title":661,"date":653,"collapsed":9,"readingTime":662},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F10.Chapter12-Arithmetic","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fchapter12-arithmetic","Chapter 12：算术运算电路 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期中试题",{"text":80,"minutes":81,"time":81,"words":81},{"stem":693,"path":694,"title":695,"date":653,"collapsed":9,"readingTime":696},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F13.PastExams\u002F3.FinalPolished","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fpastexams\u002Ffinalpolished","期末历年卷（AI 润色版）",{"text":21,"minutes":697,"time":698,"words":699},1.575,94500,315,{"stem":701,"path":702,"title":703,"date":653,"collapsed":9,"readingTime":704},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F14.ExamRecall2026","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fexamrecall2026","数字集成电路回忆 2026",{"text":60,"minutes":705,"time":706,"words":707},0.49,29400,98,{"stem":709,"path":710,"title":711,"date":653,"collapsed":9,"readingTime":712},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F2.Chapter4-Wire","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fchapter4-wire","Chapter 4：导线 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Gate",{"text":31,"minutes":729,"time":730,"words":731},8.635,518100,1727,{"stem":733,"path":734,"title":735,"date":653,"collapsed":9,"readingTime":736},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F5.Chapter7-SequentialLogic","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fchapter7-sequentiallogic","Chapter 7：时序逻辑 Sequential Logic",{"text":463,"minutes":737,"time":738,"words":739},16.645,998700,3329,{"stem":741,"path":742,"title":743,"date":653,"collapsed":9,"readingTime":744},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F6.Chapter8-Speed","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fchapter8-speed","Chapter 8：延迟与速度 Speed",{"text":745,"minutes":746,"time":747,"words":748},"33 min read",32.885,1973100,6577,{"stem":750,"path":751,"title":752,"date":653,"collapsed":9,"readingTime":753},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F7.Chapter9-Power","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fchapter9-power","Chapter 9：功耗 Power",{"text":754,"minutes":755,"time":756,"words":757},"31 min read",31.005,1860300,6201,{"stem":759,"path":760,"title":761,"date":653,"collapsed":9,"readingTime":762},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F8.Chapter10-Interconnect","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fchapter10-interconnect","Chapter 10：互连 Interconnect",{"text":463,"minutes":763,"time":764,"words":765},16.32,979200,3264,{"stem":767,"path":768,"title":769,"date":653,"collapsed":9,"readingTime":770},"posts\u002FUGCourses\u002F5.junior-spring\u002F1.digitalICDesign\u002F9.Chapter11-Timing","\u002Fugcourses\u002Fjunior-spring\u002Fdigitalicdesign\u002Fchapter11-timing","Chapter 11：时序 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read",43.985,2639100,8797,{"stem":824,"path":825,"title":826,"date":653,"collapsed":9,"readingTime":827},"posts\u002FUGCourses\u002F5.junior-spring\u002F2.computerOrganization\u002F14.L15","\u002Fugcourses\u002Fjunior-spring\u002Fcomputerorganization\u002Fl15","L15：期末复习问答",{"text":269,"minutes":828,"time":829,"words":830},9.105,546300,1821,{"stem":832,"path":833,"title":834,"date":653,"collapsed":9,"readingTime":835},"posts\u002FUGCourses\u002F5.junior-spring\u002F2.computerOrganization\u002F2.L2-Binary","\u002Fugcourses\u002Fjunior-spring\u002Fcomputerorganization\u002Fl2-binary","L2：二进制数制",{"text":80,"minutes":81,"time":81,"words":81},{"stem":837,"path":838,"title":839,"date":653,"collapsed":9,"readingTime":840},"posts\u002FUGCourses\u002F5.junior-spring\u002F2.computerOrganization\u002F3.L3-CMemory","\u002Fugcourses\u002Fjunior-spring\u002Fcomputerorganization\u002Fl3-cmemory","L3：C 语言与内存模型",{"text":841,"minutes":842,"time":843,"words":844},"98 min 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19:38:06",{"text":269,"minutes":969,"time":970,"words":971},9.26,555600,1852,{"id":973,"title":175,"body":974,"categories":6883,"collapsed":9,"date":166,"description":6884,"draft":9,"extension":6885,"hideInArchive":9,"hideInList":9,"image":6886,"meta":6887,"navigation":343,"path":174,"permalink":6886,"published":6886,"readingTime":6889,"recommend":6886,"references":6886,"seo":6890,"sitemap":6891,"stem":173,"tags":6933,"type":6935,"updated":166,"__hash__":6936},"content\u002Fposts\u002FUGCourses\u002F3.sophomore-spring\u002FDigitalSys.md",{"type":975,"value":976,"toc":6866},"minimark",[977,981,985,991,995,1000,1007,1013,1019,1142,1148,1153,1159,1168,1174,1263,1280,1298,1308,1313,1321,1340,1346,1354,1360,1365,1371,1443,1449,1458,1464,1476,1484,1491,1496,1506,1510,1513,1518,1521,1566,1569,1574,1577,1756,1759,1772,1775,1780,1783,1797,1800,1805,1808,1813,1816,2027,2030,2048,2062,2079,2082,2087,2090,2274,2277,2296,2300,2303,2317,2320,2341,2344,2354,2357,2370,2373,2541,2544,2554,2557,2564,2567,2572,2575,2584,2587,2641,2644,2662,2665,2670,2673,2681,2684,2698,2701,2709,2713,2716,2886,2889,2894,2897,2904,2907,2912,2915,2922,2925,2951,2954,2959,2962,3026,3029,3247,3250,3258,3261,3266,3269,3284,3287,3292,3295,3300,3303,3310,3314,3317,3836,3839,3847,3850,3875,3878,3890,3893,3898,3901,4001,4004,4025,4028,4182,4185,4190,4193,4200,4203,4216,4219,4226,4229,4239,4242,4247,4250,4255,4259,4347,4352,4355,4377,4380,4873,4876,4881,4884,4913,4916,4926,4929,5016,5078,5101,5104,5307,5310,5330,5333,5343,5346,5351,5355,5360,5511,5516,5521,5526,5531,5536,5543,5548,5553,5558,5563,5568,5573,5578,5587,5592,5614,5619,5624,5629,5634,5639,5774,5779,5786,5791,5869,5874,5878,5889,5986,5991,5998,6003,6008,6013,6017,6022,6027,6032,6037,6042,6046,6051,6056,6060,6065,6075,6080,6084,6089,6094,6480,6485,6490,6495,6500,6505,6510,6520,6525,6530,6535,6540,6545,6560,6565,6638,6643,6648,6653,6658,6663,6668,6673,6678,6682,6687,6700,6705,6710,6715,6720,6725,6730,6735,6740,6745,6750,6755,6760,6765,6770,6775,6780,6783,6788,6793,6798,6803,6813,6818,6823,6828,6832,6837,6842,6845,6856,6861],[978,979,980],"p",{},"Wbx Sxw Wjy",[982,983,984],"h2",{"id":984},"数字系统概念题",[978,986,987],{},[988,989],"img",{"alt":988,"src":990},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-01.png",[992,993,994],"h3",{"id":994},"历年题汇总",[996,997,999],"h4",{"id":998},"_22-23春夏","22-23春夏",[1001,1002,1003],"ol",{},[1004,1005,1006],"li",{},"多个三态门电路的输出可以直接并联，实现逻辑与（❌）",[1008,1009,1010],"blockquote",{},[978,1011,1012],{},"要OC门或者OD门，考察实现线与的方式",[1001,1014,1016],{"start":1015},2,[1004,1017,1018],{},"如果一个译码器有十六个输出，那么需要三个输入端（❌）",[1008,1020,1021],{},[978,1022,1023,1141],{},[1024,1025,1028,1064],"span",{"className":1026},[1027],"katex",[1024,1029,1032],{"className":1030},[1031],"katex-mathml",[1033,1034,1036],"math",{"xmlns":1035},"http:\u002F\u002Fwww.w3.org\u002F1998\u002FMath\u002FMathML",[1037,1038,1039,1059],"semantics",{},[1040,1041,1042,1052,1056],"mrow",{},[1043,1044,1045,1049],"msup",{},[1046,1047,1048],"mn",{},"2",[1046,1050,1051],{},"3",[1053,1054,1055],"mo",{},"=",[1046,1057,1058],{},"8",[1060,1061,1063],"annotation",{"encoding":1062},"application\u002Fx-tex","2^3=8",[1024,1065,1069,1131],{"className":1066,"ariaHidden":1068},[1067],"katex-html","true",[1024,1070,1073,1078,1119,1124,1128],{"className":1071},[1072],"base",[1024,1074],{"className":1075,"style":1077},[1076],"strut","height:0.8141em;",[1024,1079,1082,1085],{"className":1080},[1081],"mord",[1024,1083,1048],{"className":1084},[1081],[1024,1086,1089],{"className":1087},[1088],"msupsub",[1024,1090,1093],{"className":1091},[1092],"vlist-t",[1024,1094,1097],{"className":1095},[1096],"vlist-r",[1024,1098,1101],{"className":1099,"style":1077},[1100],"vlist",[1024,1102,1104,1109],{"style":1103},"top:-3.063em;margin-right:0.05em;",[1024,1105],{"className":1106,"style":1108},[1107],"pstrut","height:2.7em;",[1024,1110,1116],{"className":1111},[1112,1113,1114,1115],"sizing","reset-size6","size3","mtight",[1024,1117,1051],{"className":1118},[1081,1115],[1024,1120],{"className":1121,"style":1123},[1122],"mspace","margin-right:0.2778em;",[1024,1125,1055],{"className":1126},[1127],"mrel",[1024,1129],{"className":1130,"style":1123},[1122],[1024,1132,1134,1138],{"className":1133},[1072],[1024,1135],{"className":1136,"style":1137},[1076],"height:0.6444em;",[1024,1139,1058],{"className":1140},[1081],"所以要四个输入端",[1001,1143,1145],{"start":1144},3,[1004,1146,1147],{},"TTL门悬空相当于输入高电平，CMOS门悬空相当于输入低电平（❌）",[1008,1149,1150],{},[978,1151,1152],{},"CMOS门不可以悬空",[1001,1154,1156],{"start":1155},4,[1004,1157,1158],{},"电路测试时，SA0和SA1故障模型可以覆盖所有的故障（❌）",[1008,1160,1161],{},[978,1162,1163,1167],{},[1164,1165,1166],"strong",{},"\"所有\"","显然错误",[1001,1169,1171],{"start":1170},5,[1004,1172,1173],{},"单稳态触发器暂稳态的时长取决于触发脉冲的宽度（❌）",[1008,1175,1176],{},[978,1177,1178,1262],{},[1024,1179,1181,1213],{"className":1180},[1027],[1024,1182,1184],{"className":1183},[1031],[1033,1185,1186],{"xmlns":1035},[1037,1187,1188,1210],{},[1040,1189,1190,1194,1196,1199,1202,1205,1208],{},[1191,1192,1193],"mi",{},"T",[1053,1195,1055],{},[1191,1197,1198],{},"R",[1191,1200,1201],{},"C",[1191,1203,1204],{},"l",[1191,1206,1207],{},"n",[1046,1209,1051],{},[1060,1211,1212],{"encoding":1062},"T=RCln3",[1024,1214,1216,1237],{"className":1215,"ariaHidden":1068},[1067],[1024,1217,1219,1223,1228,1231,1234],{"className":1218},[1072],[1024,1220],{"className":1221,"style":1222},[1076],"height:0.6833em;",[1024,1224,1193],{"className":1225,"style":1227},[1081,1226],"mathnormal","margin-right:0.1389em;",[1024,1229],{"className":1230,"style":1123},[1122],[1024,1232,1055],{"className":1233},[1127],[1024,1235],{"className":1236,"style":1123},[1122],[1024,1238,1240,1244,1248,1252,1256,1259],{"className":1239},[1072],[1024,1241],{"className":1242,"style":1243},[1076],"height:0.6944em;",[1024,1245,1198],{"className":1246,"style":1247},[1081,1226],"margin-right:0.0077em;",[1024,1249,1201],{"className":1250,"style":1251},[1081,1226],"margin-right:0.0715em;",[1024,1253,1204],{"className":1254,"style":1255},[1081,1226],"margin-right:0.0197em;",[1024,1257,1207],{"className":1258},[1081,1226],[1024,1260,1051],{"className":1261},[1081],"，取决于电路本身的参数",[1001,1264,1266],{"start":1265},6,[1004,1267,1268,1272,1277],{},[1269,1270,1271],"mark",{},"设计可测试性的重要特性包括高的",[1269,1273,1274],{},[1164,1275,1276],{},"可靠性",[1269,1278,1279],{},"和高的观察性（❌）",[1008,1281,1282,1289,1295],{},[978,1283,1284,1285,1288],{},"是",[1164,1286,1287],{},"可控性","不是可靠性",[978,1290,1291,1292],{},"可控性：表示只用一个输入向量就可以使一个电路节点进入某一指定状态的难易程度，如果可以，说明容易",[1164,1293,1294],{},"控制",[978,1296,1297],{},"可观察性：表示在输出引线上观察一个节点值的难易程度",[1001,1299,1301],{"start":1300},7,[1004,1302,1303,1304,1307],{},"TTL和CMOS的",[1164,1305,1306],{},"与非门","的多余输入端均可通过电阻接电源端（✅）",[1008,1309,1310],{},[978,1311,1312],{},"注意是与非门，电阻接电源就是相当于高电平，接入“1”对于与非门而言不影响，但是注意如果是或非门等等其他的就有影响了",[1001,1314,1316],{"start":1315},8,[1004,1317,1318],{},[1269,1319,1320],{},"双稳态触发器和施密特触发器是常用的脉冲信号整形电路（❌）",[1008,1322,1323],{},[978,1324,1325,1326,1331,1334,1339],{},"注意，",[1269,1327,1328],{},[1164,1329,1330],{},"双稳态触发器（Flip-Flop）",[1164,1332,1333],{},"和",[1269,1335,1336],{},[1164,1337,1338],{},"施密特触发器（Trigger）","不一样！这题考的就是对于由于翻译原因都叫触发器的两种不同触发器的区别，只有施密特触发器的这种Trigger才有整形作用",[1001,1341,1343],{"start":1342},9,[1004,1344,1345],{},"在Verilog中，信号赋值语句按程序列出的顺序依次执行（❌）",[1008,1347,1348],{},[978,1349,1350,1353],{},[1164,1351,1352],{},"非阻塞赋值","就不是按顺序，是并行的",[1001,1355,1357],{"start":1356},10,[1004,1358,1359],{},"流水线操作算法结构一定比并行算法结构所需要的运行时间少（❌）",[1008,1361,1362],{},[978,1363,1364],{},"可以理解为CPU（流水线）和GPU（并行）这两者之间的区别，要根据具体处理任务的类型来进行区分",[1001,1366,1368],{"start":1367},11,[1004,1369,1370],{},"PROM的与阵列是全译码不可编程阵列（✅）",[1008,1372,1373,1437],{},[978,1374,1375,1376,1436],{},"全译码(",[1024,1377,1379,1397],{"className":1378},[1027],[1024,1380,1382],{"className":1381},[1031],[1033,1383,1384],{"xmlns":1035},[1037,1385,1386,1394],{},[1040,1387,1388],{},[1043,1389,1390,1392],{},[1046,1391,1048],{},[1191,1393,1207],{},[1060,1395,1396],{"encoding":1062},"2^n",[1024,1398,1400],{"className":1399,"ariaHidden":1068},[1067],[1024,1401,1403,1407],{"className":1402},[1072],[1024,1404],{"className":1405,"style":1406},[1076],"height:0.6644em;",[1024,1408,1410,1413],{"className":1409},[1081],[1024,1411,1048],{"className":1412},[1081],[1024,1414,1416],{"className":1415},[1088],[1024,1417,1419],{"className":1418},[1092],[1024,1420,1422],{"className":1421},[1096],[1024,1423,1425],{"className":1424,"style":1406},[1100],[1024,1426,1427,1430],{"style":1103},[1024,1428],{"className":1429,"style":1108},[1107],[1024,1431,1433],{"className":1432},[1112,1113,1114,1115],[1024,1434,1207],{"className":1435},[1081,1226,1115],")与阵列是可以做到的，但是与阵列不可编程（只能用一次，烧进去了里面结构就不能改了）",[978,1438,1439,1440],{},"但是",[1164,1441,1442],{},"或阵列可以编程",[1001,1444,1446],{"start":1445},12,[1004,1447,1448],{},"目前所有产品数字部件都提供边界扫描（❌）",[1008,1450,1451,1455],{},[978,1452,1453,1167],{},[1164,1454,1166],{},[978,1456,1457],{},"边界扫描：把各部件的输入输出引线连成一条串联的扫描链",[1001,1459,1461],{"start":1460},13,[1004,1462,1463],{},"一条微指令的有效持续时间为两个系统基本周期（❌）",[1008,1465,1466],{},[978,1467,1468,1471,1472,1475],{},[1164,1469,1470],{},"机器周期就是系统周期","，一个系统周期可以有多个时钟周期，所以有效持续时间为",[1164,1473,1474],{},"一个","系统基本周期",[1001,1477,1479],{"start":1478},14,[1004,1480,1481],{},[1269,1482,1483],{},"异步触发信号在整个时钟周期有效，无论时钟电平是高电平还是低电平（❌助教认为没问题是✅的）",[1008,1485,1486],{},[978,1487,1488],{},[988,1489],{"alt":988,"src":1490},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-02.png",[1001,1492,1493],{"start":686},[1004,1494,1495],{},"内建自测试技术可以实现由电路自己决定所得到的测试结果是否正确（✅）",[1008,1497,1498,1503],{},[978,1499,1500],{},[988,1501],{"alt":988,"src":1502},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-03.png",[978,1504,1505],{},"(补充讲义p50)",[996,1507,1509],{"id":1508},"_21-22春夏","21-22春夏",[978,1511,1512],{},"1、在不影响逻辑功能的情况下，CMOS 与非门的多余输入端可通过电阻接地（❌）",[1008,1514,1515],{},[978,1516,1517],{},"CMOS接地的话，不管电阻有多大，输入端都看作0，与非门接0输出肯定是1，所以废了，不可以",[978,1519,1520],{},"2、组合逻辑电路中产生竞争冒险的主要原因是输入信号受到尖峰干扰（❌）",[1008,1522,1523,1538,1544,1554,1559,1563],{},[978,1524,1525,1526,1529,1534,1537],{},"冒险的定义是",[1269,1527,1528],{},"逻辑门因输入端的竞争而导致输出产生不应有的",[1269,1530,1531],{},[1164,1532,1533],{},"尖峰干扰脉冲",[1269,1535,1536],{},"的现象","，所以题目的尖峰干扰是结果但不是原因",[1539,1540,1541],"ul",{},[1004,1542,1543],{},"竞争",[978,1545,1546,1547,1550,1551],{},"当信号通过导线和逻辑门电路时，将产生",[1164,1548,1549],{},"时间延迟","。在组合逻辑电路中，不同信号经过不同长度的导线和不同级数的逻辑门电路，",[1164,1552,1553],{},"到达另一个门的输入端的时刻会有先有后的现象",[1539,1555,1556],{},[1004,1557,1558],{},"冒险",[978,1560,1528,1561,1536],{},[1164,1562,1533],{},[978,1564,1565],{},"冒险的前提是输入端产生了竞争，但并不是是所有的竞争都会产生冒险（即有竞争不一定有冒险，但有冒险就一定存在竞争）",[978,1567,1568],{},"3、只使用与非门的逻辑电路不是时序逻辑电路（❌）",[1008,1570,1571],{},[978,1572,1573],{},"最基本的RS触发器不就是用与非门搭出来的吗？所以这个是错误的，可以是时序电路",[978,1575,1576],{},"4、只有一个变量不同的两个最大项的乘积等于各相同变量之和（✅）",[1008,1578,1579],{},[978,1580,1581,1755],{},[1024,1582,1584,1632],{"className":1583},[1027],[1024,1585,1587],{"className":1586},[1031],[1033,1588,1589],{"xmlns":1035},[1037,1590,1591,1629],{},[1040,1592,1593,1597,1600,1603,1606,1609,1611,1613,1615,1623,1625,1627],{},[1053,1594,1596],{"stretchy":1595},"false","(",[1191,1598,1599],{},"A",[1053,1601,1602],{},"+",[1191,1604,1605],{},"B",[1053,1607,1608],{"stretchy":1595},")",[1053,1610,1596],{"stretchy":1595},[1191,1612,1599],{},[1053,1614,1602],{},[1616,1617,1618,1620],"mover",{"accent":1068},[1191,1619,1605],{},[1053,1621,1622],{},"ˉ",[1053,1624,1608],{"stretchy":1595},[1053,1626,1055],{},[1191,1628,1599],{},[1060,1630,1631],{"encoding":1062},"(A+B)(A+\\bar B)=A",[1024,1633,1635,1660,1689,1746],{"className":1634,"ariaHidden":1068},[1067],[1024,1636,1638,1642,1646,1649,1653,1657],{"className":1637},[1072],[1024,1639],{"className":1640,"style":1641},[1076],"height:1em;vertical-align:-0.25em;",[1024,1643,1596],{"className":1644},[1645],"mopen",[1024,1647,1599],{"className":1648},[1081,1226],[1024,1650],{"className":1651,"style":1652},[1122],"margin-right:0.2222em;",[1024,1654,1602],{"className":1655},[1656],"mbin",[1024,1658],{"className":1659,"style":1652},[1122],[1024,1661,1663,1666,1670,1674,1677,1680,1683,1686],{"className":1662},[1072],[1024,1664],{"className":1665,"style":1641},[1076],[1024,1667,1605],{"className":1668,"style":1669},[1081,1226],"margin-right:0.0502em;",[1024,1671,1608],{"className":1672},[1673],"mclose",[1024,1675,1596],{"className":1676},[1645],[1024,1678,1599],{"className":1679},[1081,1226],[1024,1681],{"className":1682,"style":1652},[1122],[1024,1684,1602],{"className":1685},[1656],[1024,1687],{"className":1688,"style":1652},[1122],[1024,1690,1692,1696,1734,1737,1740,1743],{"className":1691},[1072],[1024,1693],{"className":1694,"style":1695},[1076],"height:1.0701em;vertical-align:-0.25em;",[1024,1697,1700],{"className":1698},[1081,1699],"accent",[1024,1701,1703],{"className":1702},[1092],[1024,1704,1706],{"className":1705},[1096],[1024,1707,1710,1720],{"className":1708,"style":1709},[1100],"height:0.8201em;",[1024,1711,1713,1717],{"style":1712},"top:-3em;",[1024,1714],{"className":1715,"style":1716},[1107],"height:3em;",[1024,1718,1605],{"className":1719,"style":1669},[1081,1226],[1024,1721,1723,1726],{"style":1722},"top:-3.2523em;",[1024,1724],{"className":1725,"style":1716},[1107],[1024,1727,1731],{"className":1728,"style":1730},[1729],"accent-body","left:-0.1667em;",[1024,1732,1622],{"className":1733},[1081],[1024,1735,1608],{"className":1736},[1673],[1024,1738],{"className":1739,"style":1123},[1122],[1024,1741,1055],{"className":1742},[1127],[1024,1744],{"className":1745,"style":1123},[1122],[1024,1747,1749,1752],{"className":1748},[1072],[1024,1750],{"className":1751,"style":1222},[1076],[1024,1753,1599],{"className":1754},[1081,1226],"，由代入定理，A可以换成别的变量和，所以正确",[978,1757,1758],{},"5、一个三态门可以通过使能电平控制实现输入或输出双向数据传输（❌）",[1008,1760,1761,1764,1769],{},[978,1762,1763],{},"一个三态门肯定是不行，这个是和传输门混淆了，传输门的结构是两个CMOS，一个通一个不通",[978,1765,1766],{},[988,1767],{"alt":988,"src":1768},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-04.png",[978,1770,1771],{},"真要实现传输门需要两个三态门",[978,1773,1774],{},"6、因为 EPROM 属于只读存储器，所以正常工作时无法对它进行写操作（✅）",[1008,1776,1777],{},[978,1778,1779],{},"ROM(Read Only Memory)肯定是只读存储器，所以正常工作时无法对它进行写操作",[978,1781,1782],{},"7、单稳态触发器有一个稳定状态，两个暂稳状态（❌）",[1008,1784,1785,1791,1794],{},[978,1786,1787,1788],{},"单稳态触发器一个稳态",[1164,1789,1790],{},"一个暂稳态",[978,1792,1793],{},"多谐振荡电路是两个暂稳态",[978,1795,1796],{},"施密特触发器两个稳态",[978,1798,1799],{},"8、固0和固1故障模型可以覆盖所有开路固定故障和短路固定故障（❌）",[1008,1801,1802],{},[978,1803,1804],{},"前面出现过",[978,1806,1807],{},"9、逻辑函数化简中无关项、任意项可以为0或1，约束项一般只能取0值（❌）",[1008,1809,1810],{},[978,1811,1812],{},"约束项只能是0，任意项可以是0或1，无关项包括了约束项和任意项，所以当无关项是约束项的时候，就不能是0或1了，所以这题是错的",[978,1814,1815],{},"10、将 JK 触发器的两个输入端连在一起作为 D 端就可以构成 D 触发器（❌）",[1008,1817,1818],{},[978,1819,1820,1821,2026],{},"K还要加一个非门注意JK触发器，",[1024,1822,1824,1867],{"className":1823},[1027],[1024,1825,1827],{"className":1826},[1031],[1033,1828,1829],{"xmlns":1035},[1037,1830,1831,1864],{},[1040,1832,1833,1842,1844,1847,1853,1855,1862],{},[1043,1834,1835,1838],{},[1191,1836,1837],{},"Q",[1053,1839,1841],{"lspace":1840,"rspace":1840},"0em","∗",[1053,1843,1055],{},[1191,1845,1846],{},"J",[1616,1848,1849,1851],{"accent":1068},[1191,1850,1837],{},[1053,1852,1622],{},[1053,1854,1602],{},[1616,1856,1857,1860],{"accent":1068},[1191,1858,1859],{},"K",[1053,1861,1622],{},[1191,1863,1837],{},[1060,1865,1866],{"encoding":1062},"Q^{*}=J\\bar Q+\\bar KQ",[1024,1868,1870,1919,1985],{"className":1869,"ariaHidden":1068},[1067],[1024,1871,1873,1877,1910,1913,1916],{"className":1872},[1072],[1024,1874],{"className":1875,"style":1876},[1076],"height:0.8831em;vertical-align:-0.1944em;",[1024,1878,1880,1883],{"className":1879},[1081],[1024,1881,1837],{"className":1882},[1081,1226],[1024,1884,1886],{"className":1885},[1088],[1024,1887,1889],{"className":1888},[1092],[1024,1890,1892],{"className":1891},[1096],[1024,1893,1896],{"className":1894,"style":1895},[1100],"height:0.6887em;",[1024,1897,1898,1901],{"style":1103},[1024,1899],{"className":1900,"style":1108},[1107],[1024,1902,1904],{"className":1903},[1112,1113,1114,1115],[1024,1905,1907],{"className":1906},[1081,1115],[1024,1908,1841],{"className":1909},[1081,1115],[1024,1911],{"className":1912,"style":1123},[1122],[1024,1914,1055],{"className":1915},[1127],[1024,1917],{"className":1918,"style":1123},[1122],[1024,1920,1922,1926,1930,1976,1979,1982],{"className":1921},[1072],[1024,1923],{"className":1924,"style":1925},[1076],"height:1.0145em;vertical-align:-0.1944em;",[1024,1927,1846],{"className":1928,"style":1929},[1081,1226],"margin-right:0.0962em;",[1024,1931,1933],{"className":1932},[1081,1699],[1024,1934,1937,1967],{"className":1935},[1092,1936],"vlist-t2",[1024,1938,1940,1962],{"className":1939},[1096],[1024,1941,1943,1951],{"className":1942,"style":1709},[1100],[1024,1944,1945,1948],{"style":1712},[1024,1946],{"className":1947,"style":1716},[1107],[1024,1949,1837],{"className":1950},[1081,1226],[1024,1952,1953,1956],{"style":1722},[1024,1954],{"className":1955,"style":1716},[1107],[1024,1957,1959],{"className":1958,"style":1730},[1729],[1024,1960,1622],{"className":1961},[1081],[1024,1963,1966],{"className":1964},[1965],"vlist-s","​",[1024,1968,1970],{"className":1969},[1096],[1024,1971,1974],{"className":1972,"style":1973},[1100],"height:0.1944em;",[1024,1975],{},[1024,1977],{"className":1978,"style":1652},[1122],[1024,1980,1602],{"className":1981},[1656],[1024,1983],{"className":1984,"style":1652},[1122],[1024,1986,1988,1991,2023],{"className":1987},[1072],[1024,1989],{"className":1990,"style":1925},[1076],[1024,1992,1994],{"className":1993},[1081,1699],[1024,1995,1997],{"className":1996},[1092],[1024,1998,2000],{"className":1999},[1096],[1024,2001,2003,2011],{"className":2002,"style":1709},[1100],[1024,2004,2005,2008],{"style":1712},[1024,2006],{"className":2007,"style":1716},[1107],[1024,2009,1859],{"className":2010,"style":1251},[1081,1226],[1024,2012,2013,2016],{"style":1722},[1024,2014],{"className":2015,"style":1716},[1107],[1024,2017,2020],{"className":2018,"style":2019},[1729],"left:-0.1944em;",[1024,2021,1622],{"className":2022},[1081],[1024,2024,1837],{"className":2025},[1081,1226],"，JK俩要是直接接一块了，那直接变成T异或Q了，那就是T触发器了",[978,2028,2029],{},"11、门电路内部三极管作为开关使用时，要提高开关速度，可以增加饱和深度（❌）",[1008,2031,2032,2043],{},[978,2033,2034,2035,2038,2039,2042],{},"现代高速数字电路（如TTL电路）会采用一些特殊设计来",[1164,2036,2037],{},"避免三极管进入深度饱和","，例如使用",[1164,2040,2041],{},"肖特基二极管","钳位（构成肖特基三极管），从而绕开深度饱和带来的电荷存储问题，大幅提高开关速度",[978,2044,2045],{},[988,2046],{"alt":988,"src":2047},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-05.png",[978,2049,2050,2051,2053,2054,2057,2058,2061],{},"12、对于一个由",[1269,2052,1306],{},"组成的 SR 锁存器，要让该锁存器",[1269,2055,2056],{},"保持","原态，输入信号应为 ",[1269,2059,2060],{},"S=R=1","（✅）",[1008,2063,2064,2067,2070,2076],{},[978,2065,2066],{},"与非门，输入端两个都是 1 的话，不影响最终输出的Q的取值，所以是保持",[978,2068,2069],{},"如果是与非门两个输入都是0，Q和Q'都是1",[978,2071,2072,2073],{},"但是如果是",[1269,2074,2075],{},"或非门，那么就是两个都是0才保持",[978,2077,2078],{},"如果是或非门两个输入都是1，Q和Q'都是0",[978,2080,2081],{},"13、摩尔型时序电路的输出既与外输入也与内部状态有关（❌）",[1008,2083,2084],{},[978,2085,2086],{},"这是米粒型",[978,2088,2089],{},"14、64Kx16 位 E'PROM 芯片有 16 条地址线和 16 条数据线（✅）",[1008,2091,2092,2269],{},[978,2093,2094,2095],{},"K是1024，64K是",[1024,2096,2098,2136],{"className":2097},[1027],[1024,2099,2101],{"className":2100},[1031],[1033,2102,2103],{"xmlns":1035},[1037,2104,2105,2133],{},[1040,2106,2107,2114,2117,2124,2126],{},[1043,2108,2109,2111],{},[1046,2110,1048],{},[1046,2112,2113],{},"6",[1053,2115,2116],{},"×",[1043,2118,2119,2121],{},[1046,2120,1048],{},[1046,2122,2123],{},"10",[1053,2125,1055],{},[1043,2127,2128,2130],{},[1046,2129,1048],{},[1046,2131,2132],{},"16",[1060,2134,2135],{"encoding":1062},"2^6 \\times 2^{10}=2^{16}",[1024,2137,2139,2184,2231],{"className":2138,"ariaHidden":1068},[1067],[1024,2140,2142,2146,2175,2178,2181],{"className":2141},[1072],[1024,2143],{"className":2144,"style":2145},[1076],"height:0.8974em;vertical-align:-0.0833em;",[1024,2147,2149,2152],{"className":2148},[1081],[1024,2150,1048],{"className":2151},[1081],[1024,2153,2155],{"className":2154},[1088],[1024,2156,2158],{"className":2157},[1092],[1024,2159,2161],{"className":2160},[1096],[1024,2162,2164],{"className":2163,"style":1077},[1100],[1024,2165,2166,2169],{"style":1103},[1024,2167],{"className":2168,"style":1108},[1107],[1024,2170,2172],{"className":2171},[1112,1113,1114,1115],[1024,2173,2113],{"className":2174},[1081,1115],[1024,2176],{"className":2177,"style":1652},[1122],[1024,2179,2116],{"className":2180},[1656],[1024,2182],{"className":2183,"style":1652},[1122],[1024,2185,2187,2190,2222,2225,2228],{"className":2186},[1072],[1024,2188],{"className":2189,"style":1077},[1076],[1024,2191,2193,2196],{"className":2192},[1081],[1024,2194,1048],{"className":2195},[1081],[1024,2197,2199],{"className":2198},[1088],[1024,2200,2202],{"className":2201},[1092],[1024,2203,2205],{"className":2204},[1096],[1024,2206,2208],{"className":2207,"style":1077},[1100],[1024,2209,2210,2213],{"style":1103},[1024,2211],{"className":2212,"style":1108},[1107],[1024,2214,2216],{"className":2215},[1112,1113,1114,1115],[1024,2217,2219],{"className":2218},[1081,1115],[1024,2220,2123],{"className":2221},[1081,1115],[1024,2223],{"className":2224,"style":1123},[1122],[1024,2226,1055],{"className":2227},[1127],[1024,2229],{"className":2230,"style":1123},[1122],[1024,2232,2234,2237],{"className":2233},[1072],[1024,2235],{"className":2236,"style":1077},[1076],[1024,2238,2240,2243],{"className":2239},[1081],[1024,2241,1048],{"className":2242},[1081],[1024,2244,2246],{"className":2245},[1088],[1024,2247,2249],{"className":2248},[1092],[1024,2250,2252],{"className":2251},[1096],[1024,2253,2255],{"className":2254,"style":1077},[1100],[1024,2256,2257,2260],{"style":1103},[1024,2258],{"className":2259,"style":1108},[1107],[1024,2261,2263],{"className":2262},[1112,1113,1114,1115],[1024,2264,2266],{"className":2265},[1081,1115],[1024,2267,2132],{"className":2268},[1081,1115],[978,2270,2271],{},[988,2272],{"alt":988,"src":2273},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-06.png",[978,2275,2276],{},"15、数字系统的控制部件通过控制线向执行部件发出的各种控制信号称为微操作（❌）",[1008,2278,2279,2285,2290],{},[978,2280,2281,2282],{},"数字系统的控制部件通过控制线向执行部件发出的",[1164,2283,2284],{},"各种控制信号称为微命令",[978,2286,2287],{},[1164,2288,2289],{},"各种控制信号的和叫做微指令（指令比命令大，指令是一串命令）",[978,2291,2292,2293],{},"执行部件接受微命令所执行的操作叫作",[1164,2294,2295],{},"微操作",[996,2297,2299],{"id":2298},"_20-21春夏","20-21春夏",[978,2301,2302],{},"1、三态门输出高阻时，其输出线上电压为高电平（❌）",[1008,2304,2305,2312],{},[978,2306,2307,2308,2311],{},"三态门高阻态上下都断开了，可以相当于是接了一个非常大的电阻然后接地，",[1164,2309,2310],{},"是不是高电平需要看剩下另一边接的是啥","，若是接TTL门电路，则可以认为是高电平，但是若接了CMOS门电路，则是接啥是啥，和电阻大小无关，还是低电平",[978,2313,2314],{},[988,2315],{"alt":988,"src":2316},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-07.png",[978,2318,2319],{},"2、逻辑式Y=(AB+ CD)'的对偶式为YD=((A+B)(C+D))'（✅）",[1008,2321,2322,2328,2333,2336],{},[978,2323,2324,2325],{},"对偶规则的定义： ",[1269,2326,2327],{},"运算取反演，显式的0 1 反演",[978,2329,2330],{},[988,2331],{"alt":988,"src":2332},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-08.png",[978,2334,2335],{},"体现在这里面就是或变与，与变或",[978,2337,2338],{},[1164,2339,2340],{},"和反演规则相比就是非保持不变",[978,2342,2343],{},"3、可以通过接入滤波电容消除竞争-冒险现象且不会影响输出电压波形（❌）",[1008,2345,2346,2351],{},[978,2347,2348],{},[988,2349],{"alt":988,"src":2350},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-09.png",[978,2352,2353],{},"滤波肯定波形变化",[978,2355,2356],{},"4、一个1024*4位的SRAM中基本存储单元的数量为1024个（❌）",[1008,2358,2359,2365],{},[978,2360,2361,2362],{},"1024*4个，",[1164,2363,2364],{},"所以一共是4096个存储单元",[978,2366,2367],{},[988,2368],{"alt":988,"src":2369},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-10.png",[978,2371,2372],{},"5、单稳态电路暂稳态维持时间的长短只取决于本身的参数，与触发脉冲无关（✅）",[1008,2374,2375,2449,2454,2536],{},[978,2376,2377,2378,2448],{},"“暂稳态维持时间”，就应该是",[1024,2379,2381,2406],{"className":2380},[1027],[1024,2382,2384],{"className":2383},[1031],[1033,2385,2386],{"xmlns":1035},[1037,2387,2388,2404],{},[1040,2389,2390,2392,2394,2396,2398,2400,2402],{},[1191,2391,1193],{},[1053,2393,1055],{},[1191,2395,1198],{},[1191,2397,1201],{},[1191,2399,1204],{},[1191,2401,1207],{},[1046,2403,1051],{},[1060,2405,1212],{"encoding":1062},[1024,2407,2409,2427],{"className":2408,"ariaHidden":1068},[1067],[1024,2410,2412,2415,2418,2421,2424],{"className":2411},[1072],[1024,2413],{"className":2414,"style":1222},[1076],[1024,2416,1193],{"className":2417,"style":1227},[1081,1226],[1024,2419],{"className":2420,"style":1123},[1122],[1024,2422,1055],{"className":2423},[1127],[1024,2425],{"className":2426,"style":1123},[1122],[1024,2428,2430,2433,2436,2439,2442,2445],{"className":2429},[1072],[1024,2431],{"className":2432,"style":1243},[1076],[1024,2434,1198],{"className":2435,"style":1247},[1081,1226],[1024,2437,1201],{"className":2438,"style":1251},[1081,1226],[1024,2440,1204],{"className":2441,"style":1255},[1081,1226],[1024,2443,1207],{"className":2444},[1081,1226],[1024,2446,1051],{"className":2447},[1081],"（当然这个和具体电路有关，这个只是举个栗子）",[978,2450,2451],{},[988,2452],{"alt":988,"src":2453},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-11.png",[978,2455,2456,2457,2535],{},"但是暂稳态能不能到下一个稳态的状态，还是和输入",[1024,2458,2460,2481],{"className":2459},[1027],[1024,2461,2463],{"className":2462},[1031],[1033,2464,2465],{"xmlns":1035},[1037,2466,2467,2478],{},[1040,2468,2469],{},[2470,2471,2472,2475],"msub",{},[1191,2473,2474],{},"V",[1191,2476,2477],{},"I",[1060,2479,2480],{"encoding":1062},"V_I",[1024,2482,2484],{"className":2483,"ariaHidden":1068},[1067],[1024,2485,2487,2491],{"className":2486},[1072],[1024,2488],{"className":2489,"style":2490},[1076],"height:0.8333em;vertical-align:-0.15em;",[1024,2492,2494,2497],{"className":2493},[1081],[1024,2495,2474],{"className":2496,"style":1652},[1081,1226],[1024,2498,2500],{"className":2499},[1088],[1024,2501,2503,2526],{"className":2502},[1092,1936],[1024,2504,2506,2523],{"className":2505},[1096],[1024,2507,2510],{"className":2508,"style":2509},[1100],"height:0.3283em;",[1024,2511,2513,2516],{"style":2512},"top:-2.55em;margin-left:-0.2222em;margin-right:0.05em;",[1024,2514],{"className":2515,"style":1108},[1107],[1024,2517,2519],{"className":2518},[1112,1113,1114,1115],[1024,2520,2477],{"className":2521,"style":2522},[1081,1226,1115],"margin-right:0.0785em;",[1024,2524,1966],{"className":2525},[1965],[1024,2527,2529],{"className":2528},[1096],[1024,2530,2533],{"className":2531,"style":2532},[1100],"height:0.15em;",[1024,2534],{},"有关的",[978,2537,2538],{},[988,2539],{"alt":988,"src":2540},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-12.png",[978,2542,2543],{},"6、为避免状态机运行中进入未定义的状态，设计时需要对所有可能状态进行完全编码（✅）",[1008,2545,2546,2551],{},[978,2547,2548],{},[988,2549],{"alt":988,"src":2550},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-13.png",[978,2552,2553],{},"其实就是为了把每一个状态都编码以确保电路能自启动，而不是“陷入”某一个状态后就没法启动了",[978,2555,2556],{},"7、在微码控制器中,微指令测试判别信息编码为“1”,表示执行这条微指令时要对系统的有关“状态标志”进行测试（✅）",[1008,2558,2559],{},[978,2560,2561],{},[988,2562],{"alt":988,"src":2563},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-14.png",[978,2565,2566],{},"8、sa0-sa1模型可以覆盖集成电路中可能的所有故障，故将其作为一种标准模型（❌）",[1008,2568,2569],{},[978,2570,2571],{},"出现了无数遍了，略过了",[978,2573,2574],{},"9、任何时钟触发器状态的改变仅与时钟的动作沿到来有关（❌）",[1008,2576,2577],{},[978,2578,2579,2580,2583],{},"触发器有电平触发和边沿触发，",[1164,2581,2582],{},"电平触发型触发器就和电平高低有关了","，只不过电平触发很容易产生“空翻”现象，所以一般常见的触发器都是边沿触发",[978,2585,2586],{},"10、冯诺依曼结构将程序和数据存储分别放在不同的物理存储空间,具有更好的灵活性和稳定性（❌）",[1008,2588,2589,2592,2603,2613,2626,2635],{},[978,2590,2591],{},"这题有两个错误",[1539,2593,2594,2597,2600],{},[1004,2595,2596],{},"冯诺依曼结构是存放到相同的物理空间",[1004,2598,2599],{},"具有更好的硬件效率",[1004,2601,2602],{},"改成哈佛就对了",[978,2604,2605,2606,2609,2610],{},"微处理器主要有两种结构，一种是",[1269,2607,2608],{},"冯诺依曼结构","也称普林斯顿结构，一种是",[1269,2611,2612],{},"哈佛",[978,2614,2615,2618,2619,2622,2623],{},[1269,2616,2617],{},"结构","，两者的区别是前者",[1269,2620,2621],{},"将程序存储和数据存储放在同一物理存储空间","，后者",[1269,2624,2625],{},"将程序",[978,2627,2628,2631,2632,2634],{},[1269,2629,2630],{},"存储和数据存储分别放在不同的物理存储空间","。冯诺依曼结构",[1269,2633,2599],{},"，",[978,2636,2637,2638],{},"哈佛结构",[1269,2639,2640],{},"具有更好的灵活性和稳定性",[978,2642,2643],{},"11、时序电路的扫描测试和自测试都不需要外部的测试向量就可以进行（❌）",[1008,2645,2646,2652,2657],{},[978,2647,2648,2651],{},[1164,2649,2650],{},"电路自测试并不需要外部的向量","并且可以以很高的速度进行",[978,2653,2654],{},[1269,2655,2656],{},"扫描测试需要外部的测试向量，但是自测试不需要",[978,2658,2659],{},[988,2660],{"alt":988,"src":2661},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-15.png",[978,2663,2664],{},"12、流水线操作算法结构一定比并行算法结构所需要的运算时间少（❌）",[1008,2666,2667],{},[978,2668,2669],{},"出现好多遍了，略",[978,2671,2672],{},"13、不同的逻辑函数表达式其逻辑功能也不同（❌）",[1008,2674,2675,2678],{},[978,2676,2677],{},"不同逻辑表达式也可以相互转化，式子不同但都是对的",[978,2679,2680],{},"非常简单一个例子，Y=A异或B和Y=A'B+AB'就是一样的，我甚至可以加几个冗余项，也是不同式子但是功能一样",[978,2682,2683],{},"14、故障覆盖率定义为由测试序列检测到的故障总数除以电路的节点数（❌）",[1008,2685,2686],{},[978,2687,2688,2689,2692,2697],{},"故障覆盖率定义为由测试序列检测到的故障总数",[1269,2690,2691],{},"除以电路节点数目的",[1269,2693,2694],{},[1164,2695,2696],{},"两倍","，因为每一个节点可以发生一个 sa0 和一个 sa1 故障。",[978,2699,2700],{},"15、CMOS与非门的多余脚悬空等效于低电平（❌）",[1008,2702,2703],{},[978,2704,2705,2706],{},"CMOS多余脚不能悬空，对于与非门的多余脚正确的做法是把它接上电阻然后",[1164,2707,2708],{},"接高电平",[996,2710,2712],{"id":2711},"_19-20春夏","19-20春夏",[978,2714,2715],{},"1.十进制数“-29”用8位二进制补码表示为 11100011（✅）",[1008,2717,2718,2723],{},[978,2719,2720],{},[1164,2721,2722],{},"负数的补码表示：先写出绝对值的二进制表示，在逐位取反加一",[978,2724,2725,2885],{},[1024,2726,2728,2764],{"className":2727},[1027],[1024,2729,2731],{"className":2730},[1031],[1033,2732,2733],{"xmlns":1035},[1037,2734,2735,2761],{},[1040,2736,2737,2739,2742,2748,2750,2752,2755],{},[1053,2738,1596],{"stretchy":1595},[1046,2740,2741],{},"29",[2470,2743,2744,2746],{},[1053,2745,1608],{"stretchy":1595},[1046,2747,2123],{},[1053,2749,1055],{},[1053,2751,1596],{"stretchy":1595},[1046,2753,2754],{},"00011101",[2470,2756,2757,2759],{},[1053,2758,1608],{"stretchy":1595},[1046,2760,1048],{},[1060,2762,2763],{"encoding":1062},"(29)_{10}=(00011101)_2",[1024,2765,2767,2833],{"className":2766,"ariaHidden":1068},[1067],[1024,2768,2770,2773,2776,2779,2824,2827,2830],{"className":2769},[1072],[1024,2771],{"className":2772,"style":1641},[1076],[1024,2774,1596],{"className":2775},[1645],[1024,2777,2741],{"className":2778},[1081],[1024,2780,2782,2785],{"className":2781},[1673],[1024,2783,1608],{"className":2784},[1673],[1024,2786,2788],{"className":2787},[1088],[1024,2789,2791,2816],{"className":2790},[1092,1936],[1024,2792,2794,2813],{"className":2793},[1096],[1024,2795,2798],{"className":2796,"style":2797},[1100],"height:0.3011em;",[1024,2799,2801,2804],{"style":2800},"top:-2.55em;margin-left:0em;margin-right:0.05em;",[1024,2802],{"className":2803,"style":1108},[1107],[1024,2805,2807],{"className":2806},[1112,1113,1114,1115],[1024,2808,2810],{"className":2809},[1081,1115],[1024,2811,2123],{"className":2812},[1081,1115],[1024,2814,1966],{"className":2815},[1965],[1024,2817,2819],{"className":2818},[1096],[1024,2820,2822],{"className":2821,"style":2532},[1100],[1024,2823],{},[1024,2825],{"className":2826,"style":1123},[1122],[1024,2828,1055],{"className":2829},[1127],[1024,2831],{"className":2832,"style":1123},[1122],[1024,2834,2836,2839,2842,2845],{"className":2835},[1072],[1024,2837],{"className":2838,"style":1641},[1076],[1024,2840,1596],{"className":2841},[1645],[1024,2843,2754],{"className":2844},[1081],[1024,2846,2848,2851],{"className":2847},[1673],[1024,2849,1608],{"className":2850},[1673],[1024,2852,2854],{"className":2853},[1088],[1024,2855,2857,2877],{"className":2856},[1092,1936],[1024,2858,2860,2874],{"className":2859},[1096],[1024,2861,2863],{"className":2862,"style":2797},[1100],[1024,2864,2865,2868],{"style":2800},[1024,2866],{"className":2867,"style":1108},[1107],[1024,2869,2871],{"className":2870},[1112,1113,1114,1115],[1024,2872,1048],{"className":2873},[1081,1115],[1024,2875,1966],{"className":2876},[1965],[1024,2878,2880],{"className":2879},[1096],[1024,2881,2883],{"className":2882,"style":2532},[1100],[1024,2884],{},"，逐位取反11100010，加一11100011",[978,2887,2888],{},"2.若取 J=K’,则可仅用 J 触发器构成 D触发器（✅）",[1008,2890,2891],{},[978,2892,2893],{},"J=k'，那么此时等于JQ'+JQ=J就是D触发器了",[978,2895,2896],{},"3.在控制器的设计中，控制时序不能有多余状态，要达到状态最简（❌）",[1008,2898,2899],{},[978,2900,2901],{},[988,2902],{"alt":988,"src":2903},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-16.png",[978,2905,2906],{},"4.因为逻辑表达式 A+B+AB=A+B 成立，所以 AB=0（❌）",[1008,2908,2909],{},[978,2910,2911],{},"你让A=B=1试试？",[978,2913,2914],{},"5.任何布尔函数都可以用与非门实现（✅）",[1008,2916,2917],{},[978,2918,2919],{},[1164,2920,2921],{},"与非门是逻辑完全门，可以用与非门构建任何逻辑门电路",[978,2923,2924],{},"6.静态 RAM 需要周期性刷新以保持数据（❌）",[1008,2926,2927],{},[978,2928,2929,2932,2935,2936,2939,2942,2943,2935,2946,2949],{},[1164,2930,2931],{},"RAM（随机存储器）",[1164,2933,2934],{},"静态RAM (SRAM"," ",[1164,2937,2938],{},"Static Random-Access Memory",[1164,2940,2941],{},") 不需要周期性刷新来保持数据","。需要周期性刷新的是",[1164,2944,2945],{},"动态RAM (DRAM",[1164,2947,2948],{},"Dynamic Random-Access Memory",[1164,2950,1608],{},[978,2952,2953],{},"7.对于任何一个逻辑函数来讲，其逻辑图都是唯一的（❌）",[1008,2955,2956],{},[978,2957,2958],{},"一个逻辑函数描述的是输入和输出之间的关系，而逻辑图是实现这种关系的物理或图形表示。由于实现方式的多样性（可以通过代数化简、使用不同的门电路组合如与非门\u002F或非门等），一个逻辑函数可以对应多个不同的、但在功能上等效的逻辑图。",[978,2960,2961],{},"8.拥有8个状态的计数器内部至少要含有8个触发器（❌）",[1008,2963,2964],{},[978,2965,2966,2967],{},"八个状态，三个触发器，",[1024,2968,2970,2988],{"className":2969},[1027],[1024,2971,2973],{"className":2972},[1031],[1033,2974,2975],{"xmlns":1035},[1037,2976,2977,2985],{},[1040,2978,2979],{},[1043,2980,2981,2983],{},[1046,2982,1048],{},[1046,2984,1051],{},[1060,2986,2987],{"encoding":1062},"2^3",[1024,2989,2991],{"className":2990,"ariaHidden":1068},[1067],[1024,2992,2994,2997],{"className":2993},[1072],[1024,2995],{"className":2996,"style":1077},[1076],[1024,2998,3000,3003],{"className":2999},[1081],[1024,3001,1048],{"className":3002},[1081],[1024,3004,3006],{"className":3005},[1088],[1024,3007,3009],{"className":3008},[1092],[1024,3010,3012],{"className":3011},[1096],[1024,3013,3015],{"className":3014,"style":1077},[1100],[1024,3016,3017,3020],{"style":1103},[1024,3018],{"className":3019,"style":1108},[1107],[1024,3021,3023],{"className":3022},[1112,1113,1114,1115],[1024,3024,1051],{"className":3025},[1081,1115],[978,3027,3028],{},"9.存储容量为128KX8位的RAM存储器,其地址线为7条、数据线为8条（❌）",[1008,3030,3031,3040],{},[978,3032,3033],{},[3034,3035,3039],"a",{"href":3036,"rel":3037},"https:\u002F\u002Fmy.feishu.cn\u002Fdocx\u002FMC7VdOGUhoBBBdxTLpUc1b5cnef#doxcngiuYnxyhGywpVyvpYISZ4c",[3038],"nofollow","【传送门】点击跳转前面题目",[978,3041,3042,3043,3242,3243,3246],{},"这题应该是",[1024,3044,3046,3089],{"className":3045},[1027],[1024,3047,3049],{"className":3048},[1031],[1033,3050,3051],{"xmlns":1035},[1037,3052,3053,3086],{},[1040,3054,3055,3058,3060,3062,3069,3071,3077,3079],{},[1046,3056,3057],{},"128",[1191,3059,1859],{},[1053,3061,1055],{},[1043,3063,3064,3066],{},[1046,3065,1048],{},[1046,3067,3068],{},"7",[1053,3070,2116],{},[1043,3072,3073,3075],{},[1046,3074,1048],{},[1046,3076,2123],{},[1053,3078,1055],{},[1043,3080,3081,3083],{},[1046,3082,1048],{},[1046,3084,3085],{},"17",[1060,3087,3088],{"encoding":1062},"128K=2^7\\times 2^{10}=2^{17}",[1024,3090,3092,3113,3157,3204],{"className":3091,"ariaHidden":1068},[1067],[1024,3093,3095,3098,3101,3104,3107,3110],{"className":3094},[1072],[1024,3096],{"className":3097,"style":1222},[1076],[1024,3099,3057],{"className":3100},[1081],[1024,3102,1859],{"className":3103,"style":1251},[1081,1226],[1024,3105],{"className":3106,"style":1123},[1122],[1024,3108,1055],{"className":3109},[1127],[1024,3111],{"className":3112,"style":1123},[1122],[1024,3114,3116,3119,3148,3151,3154],{"className":3115},[1072],[1024,3117],{"className":3118,"style":2145},[1076],[1024,3120,3122,3125],{"className":3121},[1081],[1024,3123,1048],{"className":3124},[1081],[1024,3126,3128],{"className":3127},[1088],[1024,3129,3131],{"className":3130},[1092],[1024,3132,3134],{"className":3133},[1096],[1024,3135,3137],{"className":3136,"style":1077},[1100],[1024,3138,3139,3142],{"style":1103},[1024,3140],{"className":3141,"style":1108},[1107],[1024,3143,3145],{"className":3144},[1112,1113,1114,1115],[1024,3146,3068],{"className":3147},[1081,1115],[1024,3149],{"className":3150,"style":1652},[1122],[1024,3152,2116],{"className":3153},[1656],[1024,3155],{"className":3156,"style":1652},[1122],[1024,3158,3160,3163,3195,3198,3201],{"className":3159},[1072],[1024,3161],{"className":3162,"style":1077},[1076],[1024,3164,3166,3169],{"className":3165},[1081],[1024,3167,1048],{"className":3168},[1081],[1024,3170,3172],{"className":3171},[1088],[1024,3173,3175],{"className":3174},[1092],[1024,3176,3178],{"className":3177},[1096],[1024,3179,3181],{"className":3180,"style":1077},[1100],[1024,3182,3183,3186],{"style":1103},[1024,3184],{"className":3185,"style":1108},[1107],[1024,3187,3189],{"className":3188},[1112,1113,1114,1115],[1024,3190,3192],{"className":3191},[1081,1115],[1024,3193,2123],{"className":3194},[1081,1115],[1024,3196],{"className":3197,"style":1123},[1122],[1024,3199,1055],{"className":3200},[1127],[1024,3202],{"className":3203,"style":1123},[1122],[1024,3205,3207,3210],{"className":3206},[1072],[1024,3208],{"className":3209,"style":1077},[1076],[1024,3211,3213,3216],{"className":3212},[1081],[1024,3214,1048],{"className":3215},[1081],[1024,3217,3219],{"className":3218},[1088],[1024,3220,3222],{"className":3221},[1092],[1024,3223,3225],{"className":3224},[1096],[1024,3226,3228],{"className":3227,"style":1077},[1100],[1024,3229,3230,3233],{"style":1103},[1024,3231],{"className":3232,"style":1108},[1107],[1024,3234,3236],{"className":3235},[1112,1113,1114,1115],[1024,3237,3239],{"className":3238},[1081,1115],[1024,3240,3085],{"className":3241},[1081,1115],"于是",[1164,3244,3245],{},"有17条地址线","，8条数据线是正确的",[978,3248,3249],{},"10..将OD门的输出端直接相连，就可以实现线与结构（❌）",[1008,3251,3252],{},[978,3253,3254,3255],{},"你让输出端直接相连接下一个门电路试试？",[1269,3256,3257],{},"必须要有上拉电阻才可以",[978,3259,3260],{},"11.同步时序电路和异步时序电路的主要区别是输出是否只与内部状态有关（❌）",[1008,3262,3263],{},[978,3264,3265],{},"这个属于典型的混淆概念，这个是区别摩尔型和米粒型电路的\n应该修改表述为：同步时序电路和异步时序电路的主要区别在于，电路内部的存储单元（触发器）状态更新是否受同一个全局时钟信号的控制。",[978,3267,3268],{},"12.对于一个n变量的逻辑函数，如果它的最小项表达式由k个最小项组成，则它的最大项将由 2”-k个最大项组成（✅）",[1008,3270,3271,3274,3279],{},[978,3272,3273],{},"最小项和最大项是互补的关系",[978,3275,3276],{},[988,3277],{"alt":988,"src":3278},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-17.png",[978,3280,3281],{},[988,3282],{"alt":988,"src":3283},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-18.png",[978,3285,3286],{},"13.冯诺依曼结构相比于哈佛体系结构具有更好的灵活性和稳定性，而哈佛体系结构具有更好的硬件效率（❌）",[1008,3288,3289],{},[978,3290,3291],{},"反了，冯诺伊曼架构硬件效率高；哈佛架构更灵活和稳定",[978,3293,3294],{},"14.时序电路的扫描测试和自测试都不需要外部的测试向量就可以进行（❌）",[1008,3296,3297],{},[978,3298,3299],{},"前面出现过了",[978,3301,3302],{},"15.微处理器设计除了数据通路及控制器外，还需要设计指令集（✅）",[1008,3304,3305],{},[978,3306,3307],{},[988,3308],{"alt":988,"src":3309},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-19.png",[996,3311,3313],{"id":3312},"_18-19春夏","18-19春夏",[978,3315,3316],{},"1.2019个1异或的结果再和42个0同或,得到的结果是1（✅）",[1008,3318,3319,3322,3402,3579,3582,3659,3833],{},[978,3320,3321],{},"多个异或：奇数个1则为1",[978,3323,3324,3401],{},[1024,3325,3327,3352],{"className":3326},[1027],[1024,3328,3330],{"className":3329},[1031],[1033,3331,3332],{"xmlns":1035},[1037,3333,3334,3349],{},[1040,3335,3336,3339,3342,3345,3347],{},[1191,3337,3338],{},"X",[1053,3340,3341],{},"⊕",[1046,3343,3344],{},"0",[1053,3346,1055],{},[1191,3348,3338],{},[1060,3350,3351],{"encoding":1062},"X \\oplus 0 = X",[1024,3353,3355,3374,3392],{"className":3354,"ariaHidden":1068},[1067],[1024,3356,3358,3362,3365,3368,3371],{"className":3357},[1072],[1024,3359],{"className":3360,"style":3361},[1076],"height:0.7667em;vertical-align:-0.0833em;",[1024,3363,3338],{"className":3364,"style":2522},[1081,1226],[1024,3366],{"className":3367,"style":1652},[1122],[1024,3369,3341],{"className":3370},[1656],[1024,3372],{"className":3373,"style":1652},[1122],[1024,3375,3377,3380,3383,3386,3389],{"className":3376},[1072],[1024,3378],{"className":3379,"style":1137},[1076],[1024,3381,3344],{"className":3382},[1081],[1024,3384],{"className":3385,"style":1123},[1122],[1024,3387,1055],{"className":3388},[1127],[1024,3390],{"className":3391,"style":1123},[1122],[1024,3393,3395,3398],{"className":3394},[1072],[1024,3396],{"className":3397,"style":1222},[1076],[1024,3399,3338],{"className":3400,"style":2522},[1081,1226],",所以0不影响；",[978,3403,3404,3578],{},[1024,3405,3407,3446],{"className":3406},[1027],[1024,3408,3410],{"className":3409},[1031],[1033,3411,3412],{"xmlns":1035},[1037,3413,3414,3443],{},[1040,3415,3416,3418,3420,3423,3425,3427,3429,3435,3437,3439,3441],{},[1191,3417,3338],{},[1053,3419,3341],{},[1046,3421,3422],{},"1",[1053,3424,3341],{},[1046,3426,3422],{},[1053,3428,1055],{},[1616,3430,3431,3433],{"accent":1068},[1191,3432,3338],{},[1053,3434,1622],{},[1053,3436,3341],{},[1046,3438,3422],{},[1053,3440,1055],{},[1191,3442,3338],{},[1060,3444,3445],{"encoding":1062},"X \\oplus 1 \\oplus 1 = \\bar X \\oplus 1 = X",[1024,3447,3449,3467,3486,3504,3551,3569],{"className":3448,"ariaHidden":1068},[1067],[1024,3450,3452,3455,3458,3461,3464],{"className":3451},[1072],[1024,3453],{"className":3454,"style":3361},[1076],[1024,3456,3338],{"className":3457,"style":2522},[1081,1226],[1024,3459],{"className":3460,"style":1652},[1122],[1024,3462,3341],{"className":3463},[1656],[1024,3465],{"className":3466,"style":1652},[1122],[1024,3468,3470,3474,3477,3480,3483],{"className":3469},[1072],[1024,3471],{"className":3472,"style":3473},[1076],"height:0.7278em;vertical-align:-0.0833em;",[1024,3475,3422],{"className":3476},[1081],[1024,3478],{"className":3479,"style":1652},[1122],[1024,3481,3341],{"className":3482},[1656],[1024,3484],{"className":3485,"style":1652},[1122],[1024,3487,3489,3492,3495,3498,3501],{"className":3488},[1072],[1024,3490],{"className":3491,"style":1137},[1076],[1024,3493,3422],{"className":3494},[1081],[1024,3496],{"className":3497,"style":1123},[1122],[1024,3499,1055],{"className":3500},[1127],[1024,3502],{"className":3503,"style":1123},[1122],[1024,3505,3507,3511,3542,3545,3548],{"className":3506},[1072],[1024,3508],{"className":3509,"style":3510},[1076],"height:0.9034em;vertical-align:-0.0833em;",[1024,3512,3514],{"className":3513},[1081,1699],[1024,3515,3517],{"className":3516},[1092],[1024,3518,3520],{"className":3519},[1096],[1024,3521,3523,3531],{"className":3522,"style":1709},[1100],[1024,3524,3525,3528],{"style":1712},[1024,3526],{"className":3527,"style":1716},[1107],[1024,3529,3338],{"className":3530,"style":2522},[1081,1226],[1024,3532,3533,3536],{"style":1722},[1024,3534],{"className":3535,"style":1716},[1107],[1024,3537,3539],{"className":3538,"style":1730},[1729],[1024,3540,1622],{"className":3541},[1081],[1024,3543],{"className":3544,"style":1652},[1122],[1024,3546,3341],{"className":3547},[1656],[1024,3549],{"className":3550,"style":1652},[1122],[1024,3552,3554,3557,3560,3563,3566],{"className":3553},[1072],[1024,3555],{"className":3556,"style":1137},[1076],[1024,3558,3422],{"className":3559},[1081],[1024,3561],{"className":3562,"style":1123},[1122],[1024,3564,1055],{"className":3565},[1127],[1024,3567],{"className":3568,"style":1123},[1122],[1024,3570,3572,3575],{"className":3571},[1072],[1024,3573],{"className":3574,"style":1222},[1076],[1024,3576,3338],{"className":3577,"style":2522},[1081,1226],",所以可以用交换律消去偶数个1。",[978,3580,3581],{},"多个同或：偶数个0则为1",[978,3583,3584,3658],{},[1024,3585,3587,3610],{"className":3586},[1027],[1024,3588,3590],{"className":3589},[1031],[1033,3591,3592],{"xmlns":1035},[1037,3593,3594,3607],{},[1040,3595,3596,3598,3601,3603,3605],{},[1191,3597,3338],{},[1053,3599,3600],{},"⊙",[1046,3602,3422],{},[1053,3604,1055],{},[1191,3606,3338],{},[1060,3608,3609],{"encoding":1062},"X \\odot 1 = X",[1024,3611,3613,3631,3649],{"className":3612,"ariaHidden":1068},[1067],[1024,3614,3616,3619,3622,3625,3628],{"className":3615},[1072],[1024,3617],{"className":3618,"style":3361},[1076],[1024,3620,3338],{"className":3621,"style":2522},[1081,1226],[1024,3623],{"className":3624,"style":1652},[1122],[1024,3626,3600],{"className":3627},[1656],[1024,3629],{"className":3630,"style":1652},[1122],[1024,3632,3634,3637,3640,3643,3646],{"className":3633},[1072],[1024,3635],{"className":3636,"style":1137},[1076],[1024,3638,3422],{"className":3639},[1081],[1024,3641],{"className":3642,"style":1123},[1122],[1024,3644,1055],{"className":3645},[1127],[1024,3647],{"className":3648,"style":1123},[1122],[1024,3650,3652,3655],{"className":3651},[1072],[1024,3653],{"className":3654,"style":1222},[1076],[1024,3656,3338],{"className":3657,"style":2522},[1081,1226],",所以1不影响；",[978,3660,3661,3832],{},[1024,3662,3664,3702],{"className":3663},[1027],[1024,3665,3667],{"className":3666},[1031],[1033,3668,3669],{"xmlns":1035},[1037,3670,3671,3699],{},[1040,3672,3673,3675,3677,3679,3681,3683,3685,3691,3693,3695,3697],{},[1191,3674,3338],{},[1053,3676,3600],{},[1046,3678,3344],{},[1053,3680,3600],{},[1046,3682,3344],{},[1053,3684,1055],{},[1616,3686,3687,3689],{"accent":1068},[1191,3688,3338],{},[1053,3690,1622],{},[1053,3692,3600],{},[1046,3694,3344],{},[1053,3696,1055],{},[1191,3698,3338],{},[1060,3700,3701],{"encoding":1062},"X \\odot 0 \\odot 0 = \\bar X \\odot 0 = X",[1024,3703,3705,3723,3741,3759,3805,3823],{"className":3704,"ariaHidden":1068},[1067],[1024,3706,3708,3711,3714,3717,3720],{"className":3707},[1072],[1024,3709],{"className":3710,"style":3361},[1076],[1024,3712,3338],{"className":3713,"style":2522},[1081,1226],[1024,3715],{"className":3716,"style":1652},[1122],[1024,3718,3600],{"className":3719},[1656],[1024,3721],{"className":3722,"style":1652},[1122],[1024,3724,3726,3729,3732,3735,3738],{"className":3725},[1072],[1024,3727],{"className":3728,"style":3473},[1076],[1024,3730,3344],{"className":3731},[1081],[1024,3733],{"className":3734,"style":1652},[1122],[1024,3736,3600],{"className":3737},[1656],[1024,3739],{"className":3740,"style":1652},[1122],[1024,3742,3744,3747,3750,3753,3756],{"className":3743},[1072],[1024,3745],{"className":3746,"style":1137},[1076],[1024,3748,3344],{"className":3749},[1081],[1024,3751],{"className":3752,"style":1123},[1122],[1024,3754,1055],{"className":3755},[1127],[1024,3757],{"className":3758,"style":1123},[1122],[1024,3760,3762,3765,3796,3799,3802],{"className":3761},[1072],[1024,3763],{"className":3764,"style":3510},[1076],[1024,3766,3768],{"className":3767},[1081,1699],[1024,3769,3771],{"className":3770},[1092],[1024,3772,3774],{"className":3773},[1096],[1024,3775,3777,3785],{"className":3776,"style":1709},[1100],[1024,3778,3779,3782],{"style":1712},[1024,3780],{"className":3781,"style":1716},[1107],[1024,3783,3338],{"className":3784,"style":2522},[1081,1226],[1024,3786,3787,3790],{"style":1722},[1024,3788],{"className":3789,"style":1716},[1107],[1024,3791,3793],{"className":3792,"style":1730},[1729],[1024,3794,1622],{"className":3795},[1081],[1024,3797],{"className":3798,"style":1652},[1122],[1024,3800,3600],{"className":3801},[1656],[1024,3803],{"className":3804,"style":1652},[1122],[1024,3806,3808,3811,3814,3817,3820],{"className":3807},[1072],[1024,3809],{"className":3810,"style":1137},[1076],[1024,3812,3344],{"className":3813},[1081],[1024,3815],{"className":3816,"style":1123},[1122],[1024,3818,1055],{"className":3819},[1127],[1024,3821],{"className":3822,"style":1123},[1122],[1024,3824,3826,3829],{"className":3825},[1072],[1024,3827],{"className":3828,"style":1222},[1076],[1024,3830,3338],{"className":3831,"style":2522},[1081,1226],",所以可以用交换律消去偶数个0。",[978,3834,3835],{},"2019个1异或得1，与42个0同或得1",[978,3837,3838],{},"2.摩尔 (Moore)型时序电路可以转化为米利(Mealy)型时序电路,反之则不行（❌）",[1008,3840,3841,3844],{},[978,3842,3843],{},"可以互相转化",[978,3845,3846],{},"(Tips: Mealy → Moore的大致思路: 将不同的输入拆成不同的状态)",[978,3848,3849],{},"3.产生尖峰脉冲是因为存在竞争现象,有竞争就一定会引起尖峰脉冲（❌）",[1008,3851,3852,3855,3861,3867],{},[978,3853,3854],{},"前面做到过类似的，但考察点不同",[978,3856,3857,3860],{},[1164,3858,3859],{},"竞争：","两个输入信号同时向相反的逻辑电平跳变(一个从1变为0,另一个从0变为1)的现象",[978,3862,3863,3866],{},[1164,3864,3865],{},"冒险：","逻辑门因输入端的竞争而导致输出产生不应有的尖峰干扰脉冲的现象",[978,3868,3869,3872],{},[1269,3870,3871],{},"竞争不一定有冒险，但有冒险就一定存在竞争",[1269,3873,3874],{},"，竞争是因，冒险是果",[978,3876,3877],{},"4.最小项 m3(A'BC)和m⒋(AB’C’ )具有相邻性（❌）",[1008,3879,3880,3887],{},[978,3881,3882,3883,3886],{},"若两个最小项只有一个因子不同，则称这两个最小项具有",[1164,3884,3885],{},"相邻性","。",[978,3888,3889],{},"显然没有相邻性",[978,3891,3892],{},"5.能够实现任何逻辑函数的逻辑门类型的集合,被称为逻辑门的完全集,与非门构成了完全集（✅）",[1008,3894,3895],{},[978,3896,3897],{},"做到过了，不赘述",[978,3899,3900],{},"6.一个存储容量为32×4位的存储器,可以实现四输入\\五输出的逻辑函数（❌）",[1008,3902,3903,3994],{},[978,3904,3905,3906,3989,3990,3993],{},"32个地址，",[1024,3907,3909,3933],{"className":3908},[1027],[1024,3910,3912],{"className":3911},[1031],[1033,3913,3914],{"xmlns":1035},[1037,3915,3916,3930],{},[1040,3917,3918,3921,3923],{},[1046,3919,3920],{},"32",[1053,3922,1055],{},[1043,3924,3925,3927],{},[1046,3926,1048],{},[1046,3928,3929],{},"5",[1060,3931,3932],{"encoding":1062},"32 = 2^5",[1024,3934,3936,3954],{"className":3935,"ariaHidden":1068},[1067],[1024,3937,3939,3942,3945,3948,3951],{"className":3938},[1072],[1024,3940],{"className":3941,"style":1137},[1076],[1024,3943,3920],{"className":3944},[1081],[1024,3946],{"className":3947,"style":1123},[1122],[1024,3949,1055],{"className":3950},[1127],[1024,3952],{"className":3953,"style":1123},[1122],[1024,3955,3957,3960],{"className":3956},[1072],[1024,3958],{"className":3959,"style":1077},[1076],[1024,3961,3963,3966],{"className":3962},[1081],[1024,3964,1048],{"className":3965},[1081],[1024,3967,3969],{"className":3968},[1088],[1024,3970,3972],{"className":3971},[1092],[1024,3973,3975],{"className":3974},[1096],[1024,3976,3978],{"className":3977,"style":1077},[1100],[1024,3979,3980,3983],{"style":1103},[1024,3981],{"className":3982,"style":1108},[1107],[1024,3984,3986],{"className":3985},[1112,1113,1114,1115],[1024,3987,3929],{"className":3988},[1081,1115],",故最大可以处理",[1164,3991,3992],{},"五","输入，四输入满足要求；",[978,3995,3996,3997,4000],{},"4位数据宽度，最大可以实现",[1164,3998,3999],{},"四","输出，五输出不满足。",[978,4002,4003],{},"7.冯诺依曼结构使用共用的地址和数据总线,而哈佛结构使用分离的地址总线和数据总线（❌）",[1008,4005,4006,4011,4014],{},[978,4007,4008],{},[1269,4009,4010],{},"没有很懂这个",[978,4012,4013],{},"感觉设错应该是在数据总线和地址总线都应该是独立的，不存在共用一说 √ 我们书上讲的就是冯诺依曼结构，所以两个架构离两者都是独立的",[978,4015,4016,4017,4022],{},"两个结构的区别在于",[1269,4018,4019],{},[1164,4020,4021],{},"存储",[1164,4023,4024],{},"数据与程序在不在同一空间",[978,4026,4027],{},"8.在不附加其他电路的情况下,JK触发器和T触发器可以相互转换（❌）",[1008,4029,4030,4033,4036,4041,4044,4174,4179],{},[978,4031,4032],{},"需要附加门电路",[978,4034,4035],{},"JK转T，不用",[978,4037,4038],{},[988,4039],{"alt":988,"src":4040},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-20.png",[978,4042,4043],{},"T转JK，需要",[978,4045,4046,4173],{},[1024,4047,4049,4079],{"className":4048},[1027],[1024,4050,4052],{"className":4051},[1031],[1033,4053,4054],{"xmlns":1035},[1037,4055,4056,4076],{},[1040,4057,4058,4060,4062,4064,4070,4072,4074],{},[1191,4059,1193],{},[1053,4061,1055],{},[1191,4063,1846],{},[1616,4065,4066,4068],{"accent":1068},[1191,4067,1837],{},[1053,4069,1622],{},[1053,4071,1602],{},[1191,4073,1859],{},[1191,4075,1837],{},[1060,4077,4078],{"encoding":1062},"T = J \\bar Q + KQ",[1024,4080,4082,4100,4160],{"className":4081,"ariaHidden":1068},[1067],[1024,4083,4085,4088,4091,4094,4097],{"className":4084},[1072],[1024,4086],{"className":4087,"style":1222},[1076],[1024,4089,1193],{"className":4090,"style":1227},[1081,1226],[1024,4092],{"className":4093,"style":1123},[1122],[1024,4095,1055],{"className":4096},[1127],[1024,4098],{"className":4099,"style":1123},[1122],[1024,4101,4103,4106,4109,4151,4154,4157],{"className":4102},[1072],[1024,4104],{"className":4105,"style":1925},[1076],[1024,4107,1846],{"className":4108,"style":1929},[1081,1226],[1024,4110,4112],{"className":4111},[1081,1699],[1024,4113,4115,4143],{"className":4114},[1092,1936],[1024,4116,4118,4140],{"className":4117},[1096],[1024,4119,4121,4129],{"className":4120,"style":1709},[1100],[1024,4122,4123,4126],{"style":1712},[1024,4124],{"className":4125,"style":1716},[1107],[1024,4127,1837],{"className":4128},[1081,1226],[1024,4130,4131,4134],{"style":1722},[1024,4132],{"className":4133,"style":1716},[1107],[1024,4135,4137],{"className":4136,"style":1730},[1729],[1024,4138,1622],{"className":4139},[1081],[1024,4141,1966],{"className":4142},[1965],[1024,4144,4146],{"className":4145},[1096],[1024,4147,4149],{"className":4148,"style":1973},[1100],[1024,4150],{},[1024,4152],{"className":4153,"style":1652},[1122],[1024,4155,1602],{"className":4156},[1656],[1024,4158],{"className":4159,"style":1652},[1122],[1024,4161,4163,4167,4170],{"className":4162},[1072],[1024,4164],{"className":4165,"style":4166},[1076],"height:0.8778em;vertical-align:-0.1944em;",[1024,4168,1859],{"className":4169,"style":1251},[1081,1226],[1024,4171,1837],{"className":4172},[1081,1226],"，这个要推导不很方便",[978,4175,4176],{},[988,4177],{"alt":988,"src":4178},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-21.png",[978,4180,4181],{},"当然，如果是大题可以先改造成D再改其他",[978,4183,4184],{},"9.数字系统中,并行算法结构一定比流水线操作算法结构所需要的运算时间少（❌）",[1008,4186,4187],{},[978,4188,4189],{},"“一定” + 做过多次，不赘述",[978,4191,4192],{},"10.可以用单稳态电路将不规则的矩形波变换为幅度与宽度都相同的矩形波（❌）",[1008,4194,4195],{},[978,4196,4197],{},[1269,4198,4199],{},"应该用施密特触发器来整形",[978,4201,4202],{},"11.CPU的ALU需要时钟信号协助完成运算（❌）",[1008,4204,4205],{},[978,4206,4207,4208,4211,4212,4215],{},"ALU即算术逻辑单元（Arithmetic Logic Unit）,用于完成 CPU 内的",[1164,4209,4210],{},"算术和逻辑运算","，它是一个",[1164,4213,4214],{},"组合电路","，无需时钟信号协助就能完成计算(不同于时序电路，需要时钟信号)。",[978,4217,4218],{},"12.时序图、状态转换图和状态转换表都可以用来描述同一个时序逻辑电路的逻辑功能,它们之间可以相互转换 （✅）",[1008,4220,4221],{},[978,4222,4223],{},[988,4224],{"alt":988,"src":4225},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-22.png",[978,4227,4228],{},"13.一种处理器指令架构只有一种硬件实现方式（❌）",[1008,4230,4231,4234],{},[978,4232,4233],{},"可以有多种",[978,4235,4236],{},[988,4237],{"alt":988,"src":4238},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-23.png",[978,4240,4241],{},"14.在测试电路中,边界扫描电路用于测试电路板的好坏,而内建自测试电路用于测试芯片内部的好坏（❌）",[1008,4243,4244],{},[978,4245,4246],{},"边界扫描可以测电路板，也可以测芯片；内建自测试测芯片",[978,4248,4249],{},"15.多个三态门电路的输出可以直接并接,实现逻辑与（❌）",[1008,4251,4252],{},[978,4253,4254],{},"三态门不能直接线与，会烧",[996,4256,4258],{"id":4257},"_17-18春夏","17-18春夏",[978,4260,4261,4262,4346],{},"1.十进制数 ",[1024,4263,4265,4288],{"className":4264},[1027],[1024,4266,4268],{"className":4267},[1031],[1033,4269,4270],{"xmlns":1035},[1037,4271,4272,4285],{},[1040,4273,4274,4276,4279],{},[1053,4275,1596],{"stretchy":1595},[1046,4277,4278],{},"65",[2470,4280,4281,4283],{},[1053,4282,1608],{"stretchy":1595},[1046,4284,2123],{},[1060,4286,4287],{"encoding":1062},"(65)_{10}",[1024,4289,4291],{"className":4290,"ariaHidden":1068},[1067],[1024,4292,4294,4297,4300,4303],{"className":4293},[1072],[1024,4295],{"className":4296,"style":1641},[1076],[1024,4298,1596],{"className":4299},[1645],[1024,4301,4278],{"className":4302},[1081],[1024,4304,4306,4309],{"className":4305},[1673],[1024,4307,1608],{"className":4308},[1673],[1024,4310,4312],{"className":4311},[1088],[1024,4313,4315,4338],{"className":4314},[1092,1936],[1024,4316,4318,4335],{"className":4317},[1096],[1024,4319,4321],{"className":4320,"style":2797},[1100],[1024,4322,4323,4326],{"style":2800},[1024,4324],{"className":4325,"style":1108},[1107],[1024,4327,4329],{"className":4328},[1112,1113,1114,1115],[1024,4330,4332],{"className":4331},[1081,1115],[1024,4333,2123],{"className":4334},[1081,1115],[1024,4336,1966],{"className":4337},[1965],[1024,4339,4341],{"className":4340},[1096],[1024,4342,4344],{"className":4343,"style":2532},[1100],[1024,4345],{},"的余3码编码是0111 0100（❌）",[1008,4348,4349],{},[978,4350,4351],{},"6 + 3 = 9，5 + 3 = 8，因此余3码为1001 1000。",[978,4353,4354],{},"2.实现两个一位二进制数相加的电路叫全加器（❌）",[1008,4356,4357,4367],{},[978,4358,4359,4360,4363,4364,3886],{},"如果",[1164,4361,4362],{},"不考虑有来自低位的进位","将两个1位二进制数相加，称为半加。实现半加运算的电路称为",[1164,4365,4366],{},"半加器",[978,4368,4369,4370,4373,4374,3886],{},"在将两个多位二进制数相加时，除了最低位以外，每一位都应该",[1164,4371,4372],{},"考虑来自低位的进位","，即将两个对应位的加数和来自低位的进位3个数相加。这种运算称为全加，所用的电路称为",[1164,4375,4376],{},"全加器",[978,4378,4379],{},"3.一个标准TTL反向器的输入通过5kΩ电阻接到地，则其输出为高电平（❌）",[1008,4381,4382,4387,4865,4868],{},[978,4383,4384],{},[988,4385],{"alt":988,"src":4386},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-24.png",[1024,4388,4391],{"className":4389},[4390],"katex-display",[1024,4392,4394,4474],{"className":4393},[1027],[1024,4395,4397],{"className":4396},[1031],[1033,4398,4400],{"xmlns":1035,"display":4399},"block",[1037,4401,4402,4471],{},[1040,4403,4404,4412,4414,4416,4427,4430,4442,4444,4446],{},[2470,4405,4406,4409],{},[1191,4407,4408],{},"v",[1191,4410,4411],{},"i",[1053,4413,1055],{},[1053,4415,1596],{"stretchy":1595},[2470,4417,4418,4420],{},[1191,4419,2474],{},[1040,4421,4422,4425],{},[1191,4423,4424],{},"c",[1191,4426,4424],{},[1053,4428,4429],{},"−",[2470,4431,4432,4434],{},[1191,4433,2474],{},[1040,4435,4436,4439],{},[1191,4437,4438],{},"b",[1191,4440,4441],{},"e",[1053,4443,1608],{"stretchy":1595},[1053,4445,2116],{},[4447,4448,4449,4455],"mfrac",{},[2470,4450,4451,4453],{},[1191,4452,1198],{},[1191,4454,4411],{},[1040,4456,4457,4463,4465],{},[2470,4458,4459,4461],{},[1191,4460,1198],{},[1191,4462,4411],{},[1053,4464,1602],{},[2470,4466,4467,4469],{},[1191,4468,1198],{},[1046,4470,3422],{},[1060,4472,4473],{"encoding":1062},"v_i = (V_{cc} - V_{be}) \\times \\frac{R_i}{R_i + R_1}",[1024,4475,4477,4536,4599,4664],{"className":4476,"ariaHidden":1068},[1067],[1024,4478,4480,4484,4527,4530,4533],{"className":4479},[1072],[1024,4481],{"className":4482,"style":4483},[1076],"height:0.5806em;vertical-align:-0.15em;",[1024,4485,4487,4491],{"className":4486},[1081],[1024,4488,4408],{"className":4489,"style":4490},[1081,1226],"margin-right:0.0359em;",[1024,4492,4494],{"className":4493},[1088],[1024,4495,4497,4519],{"className":4496},[1092,1936],[1024,4498,4500,4516],{"className":4499},[1096],[1024,4501,4504],{"className":4502,"style":4503},[1100],"height:0.3117em;",[1024,4505,4507,4510],{"style":4506},"top:-2.55em;margin-left:-0.0359em;margin-right:0.05em;",[1024,4508],{"className":4509,"style":1108},[1107],[1024,4511,4513],{"className":4512},[1112,1113,1114,1115],[1024,4514,4411],{"className":4515},[1081,1226,1115],[1024,4517,1966],{"className":4518},[1965],[1024,4520,4522],{"className":4521},[1096],[1024,4523,4525],{"className":4524,"style":2532},[1100],[1024,4526],{},[1024,4528],{"className":4529,"style":1123},[1122],[1024,4531,1055],{"className":4532},[1127],[1024,4534],{"className":4535,"style":1123},[1122],[1024,4537,4539,4542,4545,4590,4593,4596],{"className":4538},[1072],[1024,4540],{"className":4541,"style":1641},[1076],[1024,4543,1596],{"className":4544},[1645],[1024,4546,4548,4551],{"className":4547},[1081],[1024,4549,2474],{"className":4550,"style":1652},[1081,1226],[1024,4552,4554],{"className":4553},[1088],[1024,4555,4557,4582],{"className":4556},[1092,1936],[1024,4558,4560,4579],{"className":4559},[1096],[1024,4561,4564],{"className":4562,"style":4563},[1100],"height:0.1514em;",[1024,4565,4566,4569],{"style":2512},[1024,4567],{"className":4568,"style":1108},[1107],[1024,4570,4572],{"className":4571},[1112,1113,1114,1115],[1024,4573,4575],{"className":4574},[1081,1115],[1024,4576,4578],{"className":4577},[1081,1226,1115],"cc",[1024,4580,1966],{"className":4581},[1965],[1024,4583,4585],{"className":4584},[1096],[1024,4586,4588],{"className":4587,"style":2532},[1100],[1024,4589],{},[1024,4591],{"className":4592,"style":1652},[1122],[1024,4594,4429],{"className":4595},[1656],[1024,4597],{"className":4598,"style":1652},[1122],[1024,4600,4602,4605,4652,4655,4658,4661],{"className":4601},[1072],[1024,4603],{"className":4604,"style":1641},[1076],[1024,4606,4608,4611],{"className":4607},[1081],[1024,4609,2474],{"className":4610,"style":1652},[1081,1226],[1024,4612,4614],{"className":4613},[1088],[1024,4615,4617,4644],{"className":4616},[1092,1936],[1024,4618,4620,4641],{"className":4619},[1096],[1024,4621,4624],{"className":4622,"style":4623},[1100],"height:0.3361em;",[1024,4625,4626,4629],{"style":2512},[1024,4627],{"className":4628,"style":1108},[1107],[1024,4630,4632],{"className":4631},[1112,1113,1114,1115],[1024,4633,4635,4638],{"className":4634},[1081,1115],[1024,4636,4438],{"className":4637},[1081,1226,1115],[1024,4639,4441],{"className":4640},[1081,1226,1115],[1024,4642,1966],{"className":4643},[1965],[1024,4645,4647],{"className":4646},[1096],[1024,4648,4650],{"className":4649,"style":2532},[1100],[1024,4651],{},[1024,4653,1608],{"className":4654},[1673],[1024,4656],{"className":4657,"style":1652},[1122],[1024,4659,2116],{"className":4660},[1656],[1024,4662],{"className":4663,"style":1652},[1122],[1024,4665,4667,4671],{"className":4666},[1072],[1024,4668],{"className":4669,"style":4670},[1076],"height:2.1963em;vertical-align:-0.836em;",[1024,4672,4674,4678,4862],{"className":4673},[1081],[1024,4675],{"className":4676},[1645,4677],"nulldelimiter",[1024,4679,4681],{"className":4680},[4447],[1024,4682,4684,4853],{"className":4683},[1092,1936],[1024,4685,4687,4850],{"className":4686},[1096],[1024,4688,4691,4790,4801],{"className":4689,"style":4690},[1100],"height:1.3603em;",[1024,4692,4694,4697],{"style":4693},"top:-2.314em;",[1024,4695],{"className":4696,"style":1716},[1107],[1024,4698,4700,4741,4744,4747,4750],{"className":4699},[1081],[1024,4701,4703,4706],{"className":4702},[1081],[1024,4704,1198],{"className":4705,"style":1247},[1081,1226],[1024,4707,4709],{"className":4708},[1088],[1024,4710,4712,4733],{"className":4711},[1092,1936],[1024,4713,4715,4730],{"className":4714},[1096],[1024,4716,4718],{"className":4717,"style":4503},[1100],[1024,4719,4721,4724],{"style":4720},"top:-2.55em;margin-left:-0.0077em;margin-right:0.05em;",[1024,4722],{"className":4723,"style":1108},[1107],[1024,4725,4727],{"className":4726},[1112,1113,1114,1115],[1024,4728,4411],{"className":4729},[1081,1226,1115],[1024,4731,1966],{"className":4732},[1965],[1024,4734,4736],{"className":4735},[1096],[1024,4737,4739],{"className":4738,"style":2532},[1100],[1024,4740],{},[1024,4742],{"className":4743,"style":1652},[1122],[1024,4745,1602],{"className":4746},[1656],[1024,4748],{"className":4749,"style":1652},[1122],[1024,4751,4753,4756],{"className":4752},[1081],[1024,4754,1198],{"className":4755,"style":1247},[1081,1226],[1024,4757,4759],{"className":4758},[1088],[1024,4760,4762,4782],{"className":4761},[1092,1936],[1024,4763,4765,4779],{"className":4764},[1096],[1024,4766,4768],{"className":4767,"style":2797},[1100],[1024,4769,4770,4773],{"style":4720},[1024,4771],{"className":4772,"style":1108},[1107],[1024,4774,4776],{"className":4775},[1112,1113,1114,1115],[1024,4777,3422],{"className":4778},[1081,1115],[1024,4780,1966],{"className":4781},[1965],[1024,4783,4785],{"className":4784},[1096],[1024,4786,4788],{"className":4787,"style":2532},[1100],[1024,4789],{},[1024,4791,4793,4796],{"style":4792},"top:-3.23em;",[1024,4794],{"className":4795,"style":1716},[1107],[1024,4797],{"className":4798,"style":4800},[4799],"frac-line","border-bottom-width:0.04em;",[1024,4802,4804,4807],{"style":4803},"top:-3.677em;",[1024,4805],{"className":4806,"style":1716},[1107],[1024,4808,4810],{"className":4809},[1081],[1024,4811,4813,4816],{"className":4812},[1081],[1024,4814,1198],{"className":4815,"style":1247},[1081,1226],[1024,4817,4819],{"className":4818},[1088],[1024,4820,4822,4842],{"className":4821},[1092,1936],[1024,4823,4825,4839],{"className":4824},[1096],[1024,4826,4828],{"className":4827,"style":4503},[1100],[1024,4829,4830,4833],{"style":4720},[1024,4831],{"className":4832,"style":1108},[1107],[1024,4834,4836],{"className":4835},[1112,1113,1114,1115],[1024,4837,4411],{"className":4838},[1081,1226,1115],[1024,4840,1966],{"className":4841},[1965],[1024,4843,4845],{"className":4844},[1096],[1024,4846,4848],{"className":4847,"style":2532},[1100],[1024,4849],{},[1024,4851,1966],{"className":4852},[1965],[1024,4854,4856],{"className":4855},[1096],[1024,4857,4860],{"className":4858,"style":4859},[1100],"height:0.836em;",[1024,4861],{},[1024,4863],{"className":4864},[1673,4677],[978,4866,4867],{},"5kΩ太大了，输入为1，输出为0",[978,4869,4870],{},[1269,4871,4872],{},"一般而言临界值就是2k左右，可以当结论记",[978,4874,4875],{},"4.当时序逻辑电路存在无效循环时，该电路不能自启动（✅）",[1008,4877,4878],{},[978,4879,4880],{},"正确，好像也没什么可说的",[978,4882,4883],{},"5.如果要把一宽脉冲信号变换为窄脉冲，应采用施密特触发器（❌）",[1008,4885,4886,4889,4894,4897,4902,4905,4910],{},[978,4887,4888],{},"施密特触发器：",[978,4890,4891],{},[988,4892],{"alt":988,"src":4893},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-25.png",[978,4895,4896],{},"单稳态：",[978,4898,4899],{},[988,4900],{"alt":988,"src":4901},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-26.png",[978,4903,4904],{},"多谐：",[978,4906,4907],{},[988,4908],{"alt":988,"src":4909},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-27.png",[978,4911,4912],{},"故此处应使用单稳态",[978,4914,4915],{},"6.莫尔（Moore）状态机的输出与电路的当前状态和输入均相关（❌）",[1008,4917,4918,4923],{},[978,4919,4920],{},[988,4921],{"alt":988,"src":4922},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-28.png",[978,4924,4925],{},"Mealy有关输入，Moore无关输入",[978,4927,4928],{},"7.6个触发器组成的计数器，最多可以组成128进制的计数器（❌）",[1008,4930,4931],{},[978,4932,4933,5015],{},[1024,4934,4936,4959],{"className":4935},[1027],[1024,4937,4939],{"className":4938},[1031],[1033,4940,4941],{"xmlns":1035},[1037,4942,4943,4956],{},[1040,4944,4945,4951,4953],{},[1043,4946,4947,4949],{},[1046,4948,1048],{},[1046,4950,2113],{},[1053,4952,1055],{},[1046,4954,4955],{},"64",[1060,4957,4958],{"encoding":1062},"2^6 = 64",[1024,4960,4962,5006],{"className":4961,"ariaHidden":1068},[1067],[1024,4963,4965,4968,4997,5000,5003],{"className":4964},[1072],[1024,4966],{"className":4967,"style":1077},[1076],[1024,4969,4971,4974],{"className":4970},[1081],[1024,4972,1048],{"className":4973},[1081],[1024,4975,4977],{"className":4976},[1088],[1024,4978,4980],{"className":4979},[1092],[1024,4981,4983],{"className":4982},[1096],[1024,4984,4986],{"className":4985,"style":1077},[1100],[1024,4987,4988,4991],{"style":1103},[1024,4989],{"className":4990,"style":1108},[1107],[1024,4992,4994],{"className":4993},[1112,1113,1114,1115],[1024,4995,2113],{"className":4996},[1081,1115],[1024,4998],{"className":4999,"style":1123},[1122],[1024,5001,1055],{"className":5002},[1127],[1024,5004],{"className":5005,"style":1123},[1122],[1024,5007,5009,5012],{"className":5008},[1072],[1024,5010],{"className":5011,"style":1137},[1076],[1024,5013,4955],{"className":5014},[1081],"，最多64进制",[978,5017,5018,5019,5077],{},"8.微程序控制器中，若微指令长度为 ",[1024,5020,5022,5039],{"className":5021},[1027],[1024,5023,5025],{"className":5024},[1031],[1033,5026,5027],{"xmlns":1035},[1037,5028,5029,5037],{},[1040,5030,5031],{},[1043,5032,5033,5035],{},[1046,5034,1048],{},[1191,5036,1207],{},[1060,5038,1396],{"encoding":1062},[1024,5040,5042],{"className":5041,"ariaHidden":1068},[1067],[1024,5043,5045,5048],{"className":5044},[1072],[1024,5046],{"className":5047,"style":1406},[1076],[1024,5049,5051,5054],{"className":5050},[1081],[1024,5052,1048],{"className":5053},[1081],[1024,5055,5057],{"className":5056},[1088],[1024,5058,5060],{"className":5059},[1092],[1024,5061,5063],{"className":5062},[1096],[1024,5064,5066],{"className":5065,"style":1406},[1100],[1024,5067,5068,5071],{"style":1103},[1024,5069],{"className":5070,"style":1108},[1107],[1024,5072,5074],{"className":5073},[1112,1113,1114,1115],[1024,5075,1207],{"className":5076},[1081,1226,1115],"位，则微地址寄存器的长度为n位（✅）",[1008,5079,5080,5086,5091,5096],{},[978,5081,5082,5083],{},"微指令包含微命令、判别、下地址，",[1269,5084,5085],{},"但感觉这个长度为 2^n 位很奇怪（应该是 2^n 条）",[978,5087,5088],{},[1269,5089,5090],{},"指令长度是错的，但是如果是指指令条数那就是对的（这题感觉出题人原本意图是这个）",[978,5092,5093],{},[988,5094],{"alt":988,"src":5095},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-29.png",[978,5097,5098],{},[988,5099],{"alt":988,"src":5100},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-30.png",[978,5102,5103],{},"9.存储容量为256K×4位的RAM存储器，其地址线为8条、数据线为4条（❌）",[1008,5105,5106],{},[978,5107,5108,5306],{},[1024,5109,5111,5153],{"className":5110},[1027],[1024,5112,5114],{"className":5113},[1031],[1033,5115,5116],{"xmlns":1035},[1037,5117,5118,5150],{},[1040,5119,5120,5123,5125,5127,5133,5135,5141,5143],{},[1046,5121,5122],{},"256",[1191,5124,1859],{},[1053,5126,1055],{},[1043,5128,5129,5131],{},[1046,5130,1048],{},[1046,5132,1058],{},[1053,5134,2116],{},[1043,5136,5137,5139],{},[1046,5138,1048],{},[1046,5140,2123],{},[1053,5142,1055],{},[1043,5144,5145,5147],{},[1046,5146,1048],{},[1046,5148,5149],{},"18",[1060,5151,5152],{"encoding":1062},"256K = 2^8 \\times 2^{10} = 2^{18}",[1024,5154,5156,5177,5221,5268],{"className":5155,"ariaHidden":1068},[1067],[1024,5157,5159,5162,5165,5168,5171,5174],{"className":5158},[1072],[1024,5160],{"className":5161,"style":1222},[1076],[1024,5163,5122],{"className":5164},[1081],[1024,5166,1859],{"className":5167,"style":1251},[1081,1226],[1024,5169],{"className":5170,"style":1123},[1122],[1024,5172,1055],{"className":5173},[1127],[1024,5175],{"className":5176,"style":1123},[1122],[1024,5178,5180,5183,5212,5215,5218],{"className":5179},[1072],[1024,5181],{"className":5182,"style":2145},[1076],[1024,5184,5186,5189],{"className":5185},[1081],[1024,5187,1048],{"className":5188},[1081],[1024,5190,5192],{"className":5191},[1088],[1024,5193,5195],{"className":5194},[1092],[1024,5196,5198],{"className":5197},[1096],[1024,5199,5201],{"className":5200,"style":1077},[1100],[1024,5202,5203,5206],{"style":1103},[1024,5204],{"className":5205,"style":1108},[1107],[1024,5207,5209],{"className":5208},[1112,1113,1114,1115],[1024,5210,1058],{"className":5211},[1081,1115],[1024,5213],{"className":5214,"style":1652},[1122],[1024,5216,2116],{"className":5217},[1656],[1024,5219],{"className":5220,"style":1652},[1122],[1024,5222,5224,5227,5259,5262,5265],{"className":5223},[1072],[1024,5225],{"className":5226,"style":1077},[1076],[1024,5228,5230,5233],{"className":5229},[1081],[1024,5231,1048],{"className":5232},[1081],[1024,5234,5236],{"className":5235},[1088],[1024,5237,5239],{"className":5238},[1092],[1024,5240,5242],{"className":5241},[1096],[1024,5243,5245],{"className":5244,"style":1077},[1100],[1024,5246,5247,5250],{"style":1103},[1024,5248],{"className":5249,"style":1108},[1107],[1024,5251,5253],{"className":5252},[1112,1113,1114,1115],[1024,5254,5256],{"className":5255},[1081,1115],[1024,5257,2123],{"className":5258},[1081,1115],[1024,5260],{"className":5261,"style":1123},[1122],[1024,5263,1055],{"className":5264},[1127],[1024,5266],{"className":5267,"style":1123},[1122],[1024,5269,5271,5274],{"className":5270},[1072],[1024,5272],{"className":5273,"style":1077},[1076],[1024,5275,5277,5280],{"className":5276},[1081],[1024,5278,1048],{"className":5279},[1081],[1024,5281,5283],{"className":5282},[1088],[1024,5284,5286],{"className":5285},[1092],[1024,5287,5289],{"className":5288},[1096],[1024,5290,5292],{"className":5291,"style":1077},[1100],[1024,5293,5294,5297],{"style":1103},[1024,5295],{"className":5296,"style":1108},[1107],[1024,5298,5300],{"className":5299},[1112,1113,1114,1115],[1024,5301,5303],{"className":5302},[1081,1115],[1024,5304,5149],{"className":5305},[1081,1115],",地址线为18条",[978,5308,5309],{},"10.对于m个待处理数据的数据流，每个数据运算有L段，每段用时t的流水线操作结构，理想情况下共需运算时间T=m*t+(L-1)*t（❌答案错，应该为✅）",[1008,5311,5312,5315,5320,5325],{},[978,5313,5314],{},"就是对的",[978,5316,5317],{},[988,5318],{"alt":988,"src":5319},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-31.png",[978,5321,5322],{},[1269,5323,5324],{},"Gemini认为对",[978,5326,5327],{},[988,5328],{"alt":988,"src":5329},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-32.png",[978,5331,5332],{},"11.在一个时序逻辑电路中，消除了其中的组合逻辑电路因竞争冒险而产生的尖峰脉冲，就不会产生竞争冒险现象（❌）",[1008,5334,5335,5340],{},[978,5336,5337],{},[988,5338],{"alt":988,"src":5339},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-33.png",[978,5341,5342],{},"时序部分也存在",[978,5344,5345],{},"12.在测试电路中，边界扫描电路用于测试电路板的好坏，而内建自测试电路用于测试芯片内部的好坏（❌）",[1008,5347,5348],{},[978,5349,5350],{},"出现过，不赘述",[996,5352,5354],{"id":5353},"_16-17春夏","16-17春夏",[1001,5356,5357],{},[1004,5358,5359],{},"两个补码进行相加运算，如果最高位产生进位输出，则肯定发生溢出。 (❌)",[1008,5361,5362,5367,5375,5378,5381,5384,5389,5396,5410,5420,5434,5449,5451,5456,5461,5469,5475,5486,5499,5501],{},[978,5363,5364],{},[1164,5365,5366],{},"比较符号位的“进位输入”和“进位输出”是否相同才能判定是否真的溢出了",[1539,5368,5369,5372],{},[1004,5370,5371],{},"设 Cin 为进入符号位的进位。",[1004,5373,5374],{},"设 Cout 为符号位产生的进位。",[978,5376,5377],{},"如果 Cin!=Cout，则发生溢出。",[978,5379,5380],{},"如果 Cin=Cout，则没有溢出。",[5382,5383],"hr",{},[978,5385,5386],{},[1164,5387,5388],{},"例1：有进位输出，但没有溢出",[978,5390,5391,5392],{},"计算 ",[5393,5394,5395],"code",{"code":5395},"(-10) + 20",[1539,5397,5398,5404],{},[1004,5399,5400,5401],{},"-10 的补码是 ",[5393,5402,5403],{"code":5403},"1111 0110",[1004,5405,5406,5407],{},"20 的补码是 ",[5393,5408,5409],{"code":5409},"0001 0100",[5411,5412,5417],"pre",{"className":5413,"code":5415,"language":5416},[5414],"language-text","    1111 0110   (-10)\n+   0001 0100   (20)\n-----------------\n  1 0000 1010   (结果为 10，正确)\n","text",[5393,5418,5415],{"__ignoreMap":5419},"",[1539,5421,5422,5428],{},[1004,5423,5424,5427],{},[1164,5425,5426],{},"符号位的进位输入 Cin",": 1",[1004,5429,5430,5433],{},[1164,5431,5432],{},"符号位的进位输出 Cout",": 1 (最左边那个被舍弃的1)",[978,5435,5436,5437,5440,5441,5444,5445,5448],{},"因为 ",[1164,5438,5439],{},"Cin=Cout=1","，所以",[1164,5442,5443],{},"没有发生溢出","。尽管最高位产生了进位输出，但运算结果 ",[5393,5446,5447],{"code":5447},"0000 1010"," (十进制的10) 是完全正确的。",[5382,5450],{},[978,5452,5453],{},[1164,5454,5455],{},"例2：有溢出，但没有进位输出",[978,5457,5391,5458],{},[5393,5459,5460],{"code":5460},"80 + 80",[1539,5462,5463],{},[1004,5464,5465,5466],{},"80 的补码是 ",[5393,5467,5468],{"code":5468},"0101 0000",[5411,5470,5473],{"className":5471,"code":5472,"language":5416},[5414],"   0¹10 0000   \u003C-- 进位 (carry)\n    0101 0000   (80)\n+   0101 0000   (80)\n-----------------\n  0 1010 0000   (结果为 -96，错误)\n",[5393,5474,5472],{"__ignoreMap":5419},[1539,5476,5477,5481],{},[1004,5478,5479,5427],{},[1164,5480,5426],{},[1004,5482,5483,5485],{},[1164,5484,5432],{},": 0",[978,5487,5436,5488,5440,5491,5494,5495,5498],{},[1164,5489,5490],{},"Cin !=Cout",[1164,5492,5493],{},"发生了溢出","。两个正数相加，结果 ",[5393,5496,5497],{"code":5497},"1010 0000"," 却成了一个负数（-96），这显然是错误的。在这个例子中，虽然发生了严重的溢出，但最高位并没有产生进位输出。",[5382,5500],{},[978,5502,5503,5508],{},[1269,5504,5505],{},[1164,5506,5507],{},"不能",[1269,5509,5510],{},"简单地用“最高位是否有进位输出”来判断是否溢出。必须比较符号位的进位输入和进位输出，只有当两者不相等时，才真正发生了溢出",[1001,5512,5513],{"start":1015},[1004,5514,5515],{},"卡诺图化简得到的最简化结果是唯一的。(❌)",[1008,5517,5518],{},[978,5519,5520],{},"（可能有多个等价最简式）",[1001,5522,5523],{"start":1144},[1004,5524,5525],{},"单稳态触发器的暂稳态时间与输入触发脉冲宽度成正比。(❌)",[1008,5527,5528],{},[978,5529,5530],{},"略",[1001,5532,5533],{"start":1155},[1004,5534,5535],{},"组合逻辑电路中产生竞争冒险的主要原因是输入信号受到尖峰干扰。(❌)",[1008,5537,5538],{},[978,5539,5540],{},[1164,5541,5542],{},"信号传输延迟不一致",[1001,5544,5545],{"start":1170},[1004,5546,5547],{},"石英晶体多谐振荡器的振荡频率与电路中的R、C乘积成正比。 (❌)",[1008,5549,5550],{},[978,5551,5552],{},"只由石英晶体特性决定",[1001,5554,5555],{"start":1265},[1004,5556,5557],{},"在数字电路中，逻辑功能相同的TTL门和CMOS门芯片都可以互相替代使用。(❌)",[1008,5559,5560],{},[978,5561,5562],{},"电平标准不同且输入前接入电阻阻值不同可能会导致门电路输出完全不同",[1001,5564,5565],{"start":1300},[1004,5566,5567],{},"所有的半导体存储器在运行时都具有读写功能，所以使用时很灵活。 (❌)",[1008,5569,5570],{},[978,5571,5572],{},"ROM是只读的",[1001,5574,5575],{"start":1315},[1004,5576,5577],{},"逻辑函数 F1=ΣABCD(2,3,5,8,11,13)和 F2=ΠABCD(2,4,7,10,12,13)之间满足对偶关系。(✅)",[1008,5579,5580],{},[978,5581,5582,5583,5586],{},"这个是满足的，最小项和对偶操作后的最大项下标之和为",[5393,5584,5585],{"code":5585},"n{1'b1}"," ，本题对应为15",[1001,5588,5589],{"start":1342},[1004,5590,5591],{},"在测试电路中，响应分析驱动态压缩的输出也称为边界扫描输出。(❌)",[1008,5593,5594,5597,5602,5609],{},[978,5595,5596],{},"电路自测试中使用到响应分析驱动态压缩，是解决芯片内部逻辑测试的挑战",[978,5598,5599],{},[988,5600],{"alt":988,"src":5601},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-34.png",[978,5603,5604,5605,5608],{},"边界扫描输出主要用于测试",[1164,5606,5607],{},"芯片与芯片之间的互连","（例如电路板上的焊点和引线）以及芯片自身的I\u002FO引脚完整性。它通过在每个I\u002FO引脚旁放置一个“边界扫描单元”来实现这一目标",[978,5610,5611],{},[988,5612],{"alt":988,"src":5613},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-35.png",[1001,5615,5616],{"start":1356},[1004,5617,5618],{},"A的原码为011010，则2A对应的8位原码形式为00110100，-A的8位补码为11001011。 (❌)",[1008,5620,5621],{},[978,5622,5623],{},"补码应该是11001100，这题他忘记取反后加一了",[1001,5625,5626],{"start":1367},[1004,5627,5628],{},"流水线操作算法结构一定比并行算法结构所需要的运算时间少。 (❌)",[1008,5630,5631],{},[978,5632,5633],{},"重复",[1001,5635,5636],{"start":1445},[1004,5637,5638],{},"TTL电路的JK触发器，时钟端控5kHz脉冲，J与K悬空，则输出Q的频率为5kHz。(❌)",[1008,5640,5641],{},[978,5642,5643,5773],{},[1024,5644,5646,5673],{"className":5645},[1027],[1024,5647,5649],{"className":5648},[1031],[1033,5650,5651],{"xmlns":1035},[1037,5652,5653,5670],{},[1040,5654,5655,5661,5663],{},[1043,5656,5657,5659],{},[1191,5658,1837],{},[1053,5660,1841],{},[1053,5662,1055],{},[1616,5664,5665,5667],{"accent":1068},[1191,5666,1837],{},[1053,5668,5669],{"stretchy":1068},"‾",[1060,5671,5672],{"encoding":1062},"Q^* = \\overline{Q}",[1024,5674,5676,5720],{"className":5675,"ariaHidden":1068},[1067],[1024,5677,5679,5682,5711,5714,5717],{"className":5678},[1072],[1024,5680],{"className":5681,"style":1876},[1076],[1024,5683,5685,5688],{"className":5684},[1081],[1024,5686,1837],{"className":5687},[1081,1226],[1024,5689,5691],{"className":5690},[1088],[1024,5692,5694],{"className":5693},[1092],[1024,5695,5697],{"className":5696},[1096],[1024,5698,5700],{"className":5699,"style":1895},[1100],[1024,5701,5702,5705],{"style":1103},[1024,5703],{"className":5704,"style":1108},[1107],[1024,5706,5708],{"className":5707},[1112,1113,1114,1115],[1024,5709,1841],{"className":5710},[1656,1115],[1024,5712],{"className":5713,"style":1123},[1122],[1024,5715,1055],{"className":5716},[1127],[1024,5718],{"className":5719,"style":1123},[1122],[1024,5721,5723,5727],{"className":5722},[1072],[1024,5724],{"className":5725,"style":5726},[1076],"height:1.0778em;vertical-align:-0.1944em;",[1024,5728,5731],{"className":5729},[1081,5730],"overline",[1024,5732,5734,5765],{"className":5733},[1092,1936],[1024,5735,5737,5762],{"className":5736},[1096],[1024,5738,5741,5752],{"className":5739,"style":5740},[1100],"height:0.8833em;",[1024,5742,5743,5746],{"style":1712},[1024,5744],{"className":5745,"style":1716},[1107],[1024,5747,5749],{"className":5748},[1081],[1024,5750,1837],{"className":5751},[1081,1226],[1024,5753,5755,5758],{"style":5754},"top:-3.8033em;",[1024,5756],{"className":5757,"style":1716},[1107],[1024,5759],{"className":5760,"style":4800},[5761],"overline-line",[1024,5763,1966],{"className":5764},[1965],[1024,5766,5768],{"className":5767},[1096],[1024,5769,5771],{"className":5770,"style":1973},[1100],[1024,5772],{}," 是分频器，二分频",[1001,5775,5776],{"start":1460},[1004,5777,5778],{},"某电路有A、B、C、D、E、F六个状态，A和C、D和E、E和B、F和C分别等价，则该电路可化简为3个状态。 (❌)",[1008,5780,5781],{},[978,5782,5783],{},[1269,5784,5785],{},"啥玩意没看懂，但是按题目的意思，如果真合并的话那也是两种状态，不合并就是六个状态",[1001,5787,5788],{"start":1478},[1004,5789,5790],{},"一个16K×32bit的SRAM芯片，除了电源和接地端外，其引出线至少应该有48条。 (✅)",[1008,5792,5793,5864],{},[978,5794,5795,5798,5861],{},[1269,5796,5797],{},"16K对应",[1024,5799,5801,5820],{"className":5800},[1027],[1024,5802,5804],{"className":5803},[1031],[1033,5805,5806],{"xmlns":1035},[1037,5807,5808,5817],{},[1040,5809,5810],{},[1043,5811,5812,5814],{},[1046,5813,1048],{},[1046,5815,5816],{},"14",[1060,5818,5819],{"encoding":1062},"2^{14}",[1024,5821,5823],{"className":5822,"ariaHidden":1068},[1067],[1024,5824,5826,5829],{"className":5825},[1072],[1024,5827],{"className":5828,"style":1077},[1076],[1024,5830,5832,5835],{"className":5831},[1081],[1024,5833,1048],{"className":5834},[1081],[1024,5836,5838],{"className":5837},[1088],[1024,5839,5841],{"className":5840},[1092],[1024,5842,5844],{"className":5843},[1096],[1024,5845,5847],{"className":5846,"style":1077},[1100],[1024,5848,5849,5852],{"style":1103},[1024,5850],{"className":5851,"style":1108},[1107],[1024,5853,5855],{"className":5854},[1112,1113,1114,1115],[1024,5856,5858],{"className":5857},[1081,1115],[1024,5859,5816],{"className":5860},[1081,1115],[1269,5862,5863],{},"个存储单元，使用译码器至少需要14个端口，32bit,意味着有32根数据线，还需要有三位控制线",[978,5865,5866],{},[988,5867],{"alt":988,"src":5868},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-36.png",[1001,5870,5871],{"start":686},[1004,5872,5873],{},"微码控制器，微指令中的判别字段为0时，下址字段信息就是下条微指令的地址；微指令中的判别字段为1时，下条微指令的地址则是下址字段修改后的新地址。 (❌)",[996,5875,5877],{"id":5876},"_15-16春夏","15-16春夏",[1001,5879,5880,5883,5886],{},[1004,5881,5882],{},"\"0\" 的补码只有一种形式。  (✅)",[1004,5884,5885],{},"原码和反码均可将减法运算转化为加法运算。(❌)",[1004,5887,5888],{},"主从 JK 触发器、边缘 JK 触发器和同步 JK 触发器的逻辑功能完全相同。 (✅)",[1008,5890,5891,5894,5899,5905],{},[978,5892,5893],{},"对于所有JK触发器都遵循同一个特征表",[978,5895,5896],{},[988,5897],{"alt":988,"src":5898},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-37.png",[978,5900,5901,5902],{},"区别在于",[1164,5903,5904],{},"对时钟信号（Clock）的响应方式",[1539,5906,5907,5938,5968],{},[1004,5908,5909,5912],{},[1164,5910,5911],{},"主从JK触发器 (Master-Slave JK Flip-flop)",[1539,5913,5914,5928],{},[1004,5915,5916,5919,5920,5923,5924,5927],{},[1164,5917,5918],{},"工作方式",": 由两个锁存器（一个主、一个从）构成。它在时钟脉冲的",[1164,5921,5922],{},"整个有效电平期间","（例如，当CLK=1时）对输入J和K采样，然后在时钟电平",[1164,5925,5926],{},"跳变时","（例如，CLK从1变0）才将结果传递到最终输出Q。",[1004,5929,5930,5933,5934,5937],{},[1164,5931,5932],{},"致命缺点",": 存在“",[1164,5935,5936],{},"一次追赶","”（1s Catching）问题。如果在时钟有效电平期间（CLK=1时），输入J或K发生多次变化，主锁存器的状态会跟着变化，最终输出结果可能不是设计者想要的。它对时钟脉冲期间的干扰很敏感。",[1004,5939,5940,5943],{},[1164,5941,5942],{},"边缘JK触发器 (Edge-Triggered JK Flip-flop)",[1539,5944,5945,5958],{},[1004,5946,5947,5949,5950,5953,5954,5957],{},[1164,5948,5918],{},": 仅在时钟信号的",[1164,5951,5952],{},"上升沿","（或下降沿）的",[1164,5955,5956],{},"瞬间","对J和K输入进行采样，并立即改变输出Q。",[1004,5959,5960,5963,5964,5967],{},[1164,5961,5962],{},"巨大优势",": 它只关心时钟边沿那一瞬间的输入状态，完全忽略时钟周期内其他时间的输入变化。这使得它对干扰的",[1164,5965,5966],{},"抗扰能力极强","，电路行为更稳定、更可预测。这是现代数字设计的标准。",[1004,5969,5970,5973],{},[1164,5971,5972],{},"同步JK触发器 (Synchronous JK Flip-flop)",[1539,5974,5975],{},[1004,5976,5977,5978,5981,5982,5985],{},"这个术语本身有些笼统，因为所有JK触发器都是",[1164,5979,5980],{},"同步","元件（其状态变化与时钟同步）。在现代语境下，它通常就是指",[1164,5983,5984],{},"边缘触发式JK触发器","，以区别于已经基本淘汰的主从触发器。",[1001,5987,5988],{"start":1155},[1004,5989,5990],{},"并行加法器采用超前进位，目的是为了简化电路。(❌)",[1008,5992,5993],{},[978,5994,5995],{},[1269,5996,5997],{},"超前进位的目的是提高速度，实际上超前进位反而会使电路更复杂",[1001,5999,6000],{"start":1170},[1004,6001,6002],{},"在同步时序电路的设计中，如最简状态表中的状态数为 2^N，而又采用 N 个触发器来实现电路，则不需要检查电路的自启动性。(❌)",[1008,6004,6005],{},[978,6006,6007],{},"即便每个状态都被设计了也要看看设计出来的部分有没有自启动",[1001,6009,6010],{"start":1265},[1004,6011,6012],{},"流水线操作算法结构一定比并行算法结构所需要的运算时间少。(❌)",[1008,6014,6015],{},[978,6016,5633],{},[1001,6018,6019],{"start":1300},[1004,6020,6021],{},"摩尔型时序逻辑电路的输出与输入和电路当前状态均有关。 (❌)",[1008,6023,6024],{},[978,6025,6026],{},"米利型才是，摩尔型只与当前电路状态有关",[1001,6028,6029],{"start":1315},[1004,6030,6031],{},"所有的半导体存储器在运行时都具有读写功能。 (❌)",[1008,6033,6034],{},[978,6035,6036],{},"不可以",[1001,6038,6039],{"start":1342},[1004,6040,6041],{},"在电路测试中 SA0 和 SA1 故障模型可以覆盖集成电路中的所有可能的故障。 (❌)",[1008,6043,6044],{},[978,6045,5633],{},[1001,6047,6048],{"start":1356},[1004,6049,6050],{},"冯诺依曼结构相比于哈佛体系结构具有更好的灵活性和稳定性，而哈佛体系结构具有更好的硬件效率。(❌)",[1008,6052,6053],{},[978,6054,6055],{},"重复了",[996,6057,6059],{"id":6058},"_14-15春夏","14-15春夏",[1001,6061,6062],{},[1004,6063,6064],{},"处理器可以分为两个部分:数据通路和控制电路 (✅)",[1008,6066,6067,6070],{},[978,6068,6069],{},"那就记下来吧",[978,6071,6072],{},[988,6073],{"alt":988,"src":6074},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-38.png",[1001,6076,6077],{"start":1015},[1004,6078,6079],{},"一般 TTL 门电路的输出端可以直接相连，实现线与 (❌)",[1008,6081,6082],{},[978,6083,3299],{},[1001,6085,6086],{"start":1144},[1004,6087,6088],{},"CMOS 与非门和 TTL 与非门的逻辑功能不一样 (❌)",[1008,6090,6091],{},[978,6092,6093],{},"都是与非还能不一样？",[1001,6095,6096],{"start":1155},[1004,6097,6098,6099,6272,6273,6354,6355,6479],{},"JK触发器在时钟脉冲的作用下，如果要使 ",[1024,6100,6102,6138],{"className":6101},[1027],[1024,6103,6105],{"className":6104},[1031],[1033,6106,6107],{"xmlns":1035},[1037,6108,6109,6135],{},[1040,6110,6111,6123,6125],{},[1043,6112,6113,6115],{},[1191,6114,1837],{},[1040,6116,6117,6119,6121],{},[1191,6118,1207],{},[1053,6120,1602],{},[1046,6122,3422],{},[1053,6124,1055],{},[1043,6126,6127,6133],{},[1616,6128,6129,6131],{"accent":1068},[1191,6130,1837],{},[1053,6132,1622],{},[1191,6134,1207],{},[1060,6136,6137],{"encoding":1062},"Q^{n + 1} = \\bar Q^{n}",[1024,6139,6141,6195],{"className":6140,"ariaHidden":1068},[1067],[1024,6142,6144,6148,6186,6189,6192],{"className":6143},[1072],[1024,6145],{"className":6146,"style":6147},[1076],"height:1.0085em;vertical-align:-0.1944em;",[1024,6149,6151,6154],{"className":6150},[1081],[1024,6152,1837],{"className":6153},[1081,1226],[1024,6155,6157],{"className":6156},[1088],[1024,6158,6160],{"className":6159},[1092],[1024,6161,6163],{"className":6162},[1096],[1024,6164,6166],{"className":6165,"style":1077},[1100],[1024,6167,6168,6171],{"style":1103},[1024,6169],{"className":6170,"style":1108},[1107],[1024,6172,6174],{"className":6173},[1112,1113,1114,1115],[1024,6175,6177,6180,6183],{"className":6176},[1081,1115],[1024,6178,1207],{"className":6179},[1081,1226,1115],[1024,6181,1602],{"className":6182},[1656,1115],[1024,6184,3422],{"className":6185},[1081,1115],[1024,6187],{"className":6188,"style":1123},[1122],[1024,6190,1055],{"className":6191},[1127],[1024,6193],{"className":6194,"style":1123},[1122],[1024,6196,6198,6201],{"className":6197},[1072],[1024,6199],{"className":6200,"style":1925},[1076],[1024,6202,6204,6246],{"className":6203},[1081],[1024,6205,6207],{"className":6206},[1081,1699],[1024,6208,6210,6238],{"className":6209},[1092,1936],[1024,6211,6213,6235],{"className":6212},[1096],[1024,6214,6216,6224],{"className":6215,"style":1709},[1100],[1024,6217,6218,6221],{"style":1712},[1024,6219],{"className":6220,"style":1716},[1107],[1024,6222,1837],{"className":6223},[1081,1226],[1024,6225,6226,6229],{"style":1722},[1024,6227],{"className":6228,"style":1716},[1107],[1024,6230,6232],{"className":6231,"style":1730},[1729],[1024,6233,1622],{"className":6234},[1081],[1024,6236,1966],{"className":6237},[1965],[1024,6239,6241],{"className":6240},[1096],[1024,6242,6244],{"className":6243,"style":1973},[1100],[1024,6245],{},[1024,6247,6249],{"className":6248},[1088],[1024,6250,6252],{"className":6251},[1092],[1024,6253,6255],{"className":6254},[1096],[1024,6256,6258],{"className":6257,"style":1406},[1100],[1024,6259,6260,6263],{"style":1103},[1024,6261],{"className":6262,"style":1108},[1107],[1024,6264,6266],{"className":6265},[1112,1113,1114,1115],[1024,6267,6269],{"className":6268},[1081,1115],[1024,6270,1207],{"className":6271},[1081,1226,1115],"，则输入信号JK应为 ",[1024,6274,6276,6298],{"className":6275},[1027],[1024,6277,6279],{"className":6278},[1031],[1033,6280,6281],{"xmlns":1035},[1037,6282,6283,6295],{},[1040,6284,6285,6287,6289],{},[1191,6286,1846],{},[1053,6288,1055],{},[1043,6290,6291,6293],{},[1191,6292,1837],{},[1191,6294,1207],{},[1060,6296,6297],{"encoding":1062},"J = Q^n",[1024,6299,6301,6319],{"className":6300,"ariaHidden":1068},[1067],[1024,6302,6304,6307,6310,6313,6316],{"className":6303},[1072],[1024,6305],{"className":6306,"style":1222},[1076],[1024,6308,1846],{"className":6309,"style":1929},[1081,1226],[1024,6311],{"className":6312,"style":1123},[1122],[1024,6314,1055],{"className":6315},[1127],[1024,6317],{"className":6318,"style":1123},[1122],[1024,6320,6322,6325],{"className":6321},[1072],[1024,6323],{"className":6324,"style":4166},[1076],[1024,6326,6328,6331],{"className":6327},[1081],[1024,6329,1837],{"className":6330},[1081,1226],[1024,6332,6334],{"className":6333},[1088],[1024,6335,6337],{"className":6336},[1092],[1024,6338,6340],{"className":6339},[1096],[1024,6341,6343],{"className":6342,"style":1406},[1100],[1024,6344,6345,6348],{"style":1103},[1024,6346],{"className":6347,"style":1108},[1107],[1024,6349,6351],{"className":6350},[1112,1113,1114,1115],[1024,6352,1207],{"className":6353},[1081,1226,1115],"， ",[1024,6356,6358,6384],{"className":6357},[1027],[1024,6359,6361],{"className":6360},[1031],[1033,6362,6363],{"xmlns":1035},[1037,6364,6365,6381],{},[1040,6366,6367,6369,6371],{},[1191,6368,1859],{},[1053,6370,1055],{},[1043,6372,6373,6379],{},[1616,6374,6375,6377],{"accent":1068},[1191,6376,1837],{},[1053,6378,1622],{},[1191,6380,1207],{},[1060,6382,6383],{"encoding":1062},"K = \\bar Q^n",[1024,6385,6387,6405],{"className":6386,"ariaHidden":1068},[1067],[1024,6388,6390,6393,6396,6399,6402],{"className":6389},[1072],[1024,6391],{"className":6392,"style":1222},[1076],[1024,6394,1859],{"className":6395,"style":1251},[1081,1226],[1024,6397],{"className":6398,"style":1123},[1122],[1024,6400,1055],{"className":6401},[1127],[1024,6403],{"className":6404,"style":1123},[1122],[1024,6406,6408,6411],{"className":6407},[1072],[1024,6409],{"className":6410,"style":1925},[1076],[1024,6412,6414,6456],{"className":6413},[1081],[1024,6415,6417],{"className":6416},[1081,1699],[1024,6418,6420,6448],{"className":6419},[1092,1936],[1024,6421,6423,6445],{"className":6422},[1096],[1024,6424,6426,6434],{"className":6425,"style":1709},[1100],[1024,6427,6428,6431],{"style":1712},[1024,6429],{"className":6430,"style":1716},[1107],[1024,6432,1837],{"className":6433},[1081,1226],[1024,6435,6436,6439],{"style":1722},[1024,6437],{"className":6438,"style":1716},[1107],[1024,6440,6442],{"className":6441,"style":1730},[1729],[1024,6443,1622],{"className":6444},[1081],[1024,6446,1966],{"className":6447},[1965],[1024,6449,6451],{"className":6450},[1096],[1024,6452,6454],{"className":6453,"style":1973},[1100],[1024,6455],{},[1024,6457,6459],{"className":6458},[1088],[1024,6460,6462],{"className":6461},[1092],[1024,6463,6465],{"className":6464},[1096],[1024,6466,6468],{"className":6467,"style":1406},[1100],[1024,6469,6470,6473],{"style":1103},[1024,6471],{"className":6472,"style":1108},[1107],[1024,6474,6476],{"className":6475},[1112,1113,1114,1115],[1024,6477,1207],{"className":6478},[1081,1226,1115]," (❌)",[1008,6481,6482],{},[978,6483,6484],{},"要是这样做了之后JK触发器就变成D触发器了，显然不对",[1001,6486,6487],{"start":1170},[1004,6488,6489],{},"具有记忆功能的各类触发器是构成时序逻辑电路的基本单元 (✅)",[1008,6491,6492],{},[978,6493,6494],{},"记下来吧，纯定义问题",[1001,6496,6497],{"start":1265},[1004,6498,6499],{},"石英晶体多谐振荡器的振荡频率与电路中的R、C乘积成正比 (❌)",[1008,6501,6502],{},[978,6503,6504],{},"石英晶振就和石英本身有关了，和RC肯定无关了",[1001,6506,6507],{"start":1300},[1004,6508,6509],{},"状态简化中，若 S1、S2 两状态的输出不同，则S1、S2 两状态肯定不等价。由两个 TTL 或非门构成的基本 RS 触发器，当 R=S=0 时，触发器的状态为不定 (✅)",[1008,6511,6512,6515],{},[978,6513,6514],{},"这个就是考状态简化的定义了",[978,6516,6517],{},[988,6518],{"alt":988,"src":6519},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-39.png",[1001,6521,6522],{"start":1315},[1004,6523,6524],{},"由两个 TTL 或非门构成的基本 RS 触发器，当 R=S=0 时，触发器的状态为不定 (❌)",[1008,6526,6527],{},[978,6528,6529],{},"应该是保持状态，不是不定状态，对于或非门而言，不定状态是指R=S=1",[1001,6531,6532],{"start":1342},[1004,6533,6534],{},"格雷码具有任何相邻码只有一位码元不同的特性 (✅)",[1008,6536,6537],{},[978,6538,6539],{},"定义问题",[1001,6541,6542],{"start":1356},[1004,6543,6544],{},"组合逻辑电路中产生竞争冒险的主要原因是输入信号受到尖峰干扰 (❌)",[1008,6546,6547,6557],{},[978,6548,1525,6549,6551,6555,1537],{},[1269,6550,1528],{},[1269,6552,6553],{},[1164,6554,1533],{},[1269,6556,1536],{},[978,6558,6559],{},"前面出现过的",[1001,6561,6562],{"start":1367},[1004,6563,6564],{},"对于一个存储容量位32KX16位的RAM有512K个地址单元 (❌)",[1008,6566,6567,6570,6577,6601,6608,6632],{},[978,6568,6569],{},"512K是指存储容量，地址单元就是32K",[978,6571,6572,6573,6576],{},"存储容量的表示方法 ",[1164,6574,6575],{},"“N x M位”"," 有着明确的含义：",[1539,6578,6579,6588],{},[1004,6580,6581,6584,6585,3886],{},[1164,6582,6583],{},"N",": 表示该存储器有多少个",[1164,6586,6587],{},"可独立寻址的存储单元（地址单元）",[1004,6589,6590,6593,6594,6597,6598,3886],{},[1164,6591,6592],{},"M",": 表示",[1164,6595,6596],{},"每个","存储单元包含多少个二进制位（bit），即",[1164,6599,6600],{},"字长 (Word Length)",[978,6602,6603,6604,6607],{},"现在我们来看题目中的“",[1164,6605,6606],{},"32K x 16位","”：",[1539,6609,6610,6622],{},[1004,6611,6612,6615,6616,6618,6619,6621],{},[1164,6613,6614],{},"32K",": 这部分直接告诉我们，这个RAM有 ",[1164,6617,6614],{}," 个可独立寻址的存储单元。",[5393,6620,1859],{"code":1859},"在这里是 210=1024，所以总共有 32×1024=32,768 个地址单元。",[1004,6623,6624,6627,6628,6631],{},[1164,6625,6626],{},"16位",": 这部分说明了",[1164,6629,6630],{},"每一个","地址单元存放的数据是16位宽。",[978,6633,6634,6635,6637],{},"因此，这个RAM的地址单元数量就是 ",[1164,6636,6614],{},"，而不是512K。",[1001,6639,6640],{"start":1445},[1004,6641,6642],{},"或非门多余的输入端均可以悬空 (❌)",[1008,6644,6645],{},[978,6646,6647],{},"CMOS不允许悬空",[1001,6649,6650],{"start":1460},[1004,6651,6652],{},"单稳态触发器的暂稳态时间与输入触发脉冲宽度成正比 (❌)",[1008,6654,6655],{},[978,6656,6657],{},"只和本身RC有关",[1001,6659,6660],{"start":1478},[1004,6661,6662],{},"由与、或、非门电路构成的逻辑电路一定是组合逻辑电路 (❌)",[1008,6664,6665],{},[978,6666,6667],{},"触发器不就是由与非门或非门搭出来的吗（笑）",[1001,6669,6670],{"start":686},[1004,6671,6672],{},"冯诺依曼结构和哈佛结构的区别是:前者将程序存储和数据存储放在同一物理存储空间，后者将程序和数据存储分别放在不同的物理存储空间 (✅)",[1008,6674,6675],{},[978,6676,6677],{},"补充上定义，前面出现过的",[996,6679,6681],{"id":6680},"_13-14春夏","13-14春夏",[1001,6683,6684],{},[1004,6685,6686],{},"2014个“1”异或的结果再与 117 个“0”同或，得到的结果是“0”(❌)",[1008,6688,6689,6692,6695],{},[978,6690,6691],{},"2014偶数个1，异或完是0，然后就是118个0进行同或，偶数个0同或结果为1",[978,6693,6694],{},"关于异或，就是检验多少个1，检奇，1的数量为奇则结果为1",[978,6696,6697],{},[1269,6698,6699],{},"而同或就反着来了，检验多少个0，检偶，0的数量为偶数则结果为1",[1001,6701,6702],{"start":1015},[1004,6703,6704],{},"有一 8421BCD 数码 10010011，它相当于十进制数“147”(❌)",[1008,6706,6707],{},[978,6708,6709],{},"这种编码要拆成4位和4位来看",[1001,6711,6712],{"start":1144},[1004,6713,6714],{},"三态门输出为高阻时，其输出线上电压为高电平(❌)",[1008,6716,6717],{},[978,6718,6719],{},"前面出现过的，要看连的那一端",[1001,6721,6722],{"start":1155},[1004,6723,6724],{},"任意两个最大项之和恒为“1” (✅)",[1008,6726,6727],{},[978,6728,6729],{},"最大项是和式，再和，肯定会有A和A’这种出现的，结果为1",[1001,6731,6732],{"start":1170},[1004,6733,6734],{},"CMOS 与非门的多余脚悬空等效于低电平(❌)",[1008,6736,6737],{},[978,6738,6739],{},"不能悬空",[1001,6741,6742],{"start":1265},[1004,6743,6744],{},"将 JK 触发器的 K端接到触发器反向输出端，把J端接到输入 T，就能把JK触发器改造成 T触发器(❌)",[1008,6746,6747],{},[978,6748,6749],{},"T触发器是把JK直接连到一起了",[1001,6751,6752],{"start":1300},[1004,6753,6754],{},"超前进位加法器比串行进位加法器速度慢(❌)",[1008,6756,6757],{},[978,6758,6759],{},"超前进位更快",[1001,6761,6762],{"start":1315},[1004,6763,6764],{},"组合逻辑电路产生竞争冒险的内因是信号在电路内部的电平不一致而且有尖峰脉冲噪声存在(❌)",[1008,6766,6767],{},[978,6768,6769],{},"出现好多遍了",[1001,6771,6772],{"start":1342},[1004,6773,6774],{},"施密特触发器电路具有两个稳态且每个稳态需要相应的输入条件维持 (✅)",[1008,6776,6777],{},[978,6778,6779],{},"是的，这个就是定义问题了吧",[978,6781,6782],{},"10.五进制计数器的有效状态为5个 (✅)",[1008,6784,6785],{},[978,6786,6787],{},"0-1-2-3-4-0，所以是五个",[1001,6789,6790],{"start":1367},[1004,6791,6792],{},"当时序逻辑电路存在无效循环时该电路不能自启动 (✅)",[1008,6794,6795],{},[978,6796,6797],{},"对的，这个就是自启动的定义",[1001,6799,6800],{"start":1445},[1004,6801,6802],{},"米里(Mealy)状态机和莫尔(Moore)状态机可以相互转换(❌，我感觉是✅的)",[1008,6804,6805,6810],{},[978,6806,6807],{},[1269,6808,6809],{},"问了刘鹏，他也说可以",[978,6811,6812],{},"前面有，可以",[1001,6814,6815],{"start":1460},[1004,6816,6817],{},"最少 64 片容量为 256x4 的 RAM 可组合成容量为 4KX8的 RAM(❌)",[1008,6819,6820],{},[978,6821,6822],{},"可以算一下，应该是32片",[1001,6824,6825],{"start":1478},[1004,6826,6827],{},"流水线操作算法结构一定比并行算法结构所需要的运算时间少(❌)",[1008,6829,6830],{},[978,6831,5633],{},[1001,6833,6834],{"start":686},[1004,6835,6836],{},"大批量定型产品的生产因为是成熟设计所以不需要测试(❌)",[1008,6838,6839],{},[978,6840,6841],{},"一眼错",[992,6843,6844],{"id":6844},"别的鸡脚旮旯的概念",[1001,6846,6847,6853],{},[1004,6848,6849,6852],{},[5393,6850,6851],{"code":6851},"a^b"," 指的是按位异或运算",[1004,6854,6855],{},"555触发器这个RS触发器的封装取出来的值是Q'",[978,6857,6858],{},[988,6859],{"alt":988,"src":6860},"\u002Fimg\u002FDigitalSys\u002FDigitalSys-40.png",[1001,6862,6863],{"start":1144},[1004,6864,6865],{},"PAL Programable Array Logic 与门可编程，或门不可编程。但是 PLA 与或门都可编程",{"title":5419,"searchDepth":1155,"depth":1155,"links":6867},[6868],{"id":984,"depth":1015,"text":984,"children":6869},[6870,6882],{"id":994,"depth":1144,"text":994,"children":6871},[6872,6873,6874,6875,6876,6877,6878,6879,6880,6881],{"id":998,"depth":1155,"text":999},{"id":1508,"depth":1155,"text":1509},{"id":2298,"depth":1155,"text":2299},{"id":2711,"depth":1155,"text":2712},{"id":3312,"depth":1155,"text":3313},{"id":4257,"depth":1155,"text":4258},{"id":5353,"depth":1155,"text":5354},{"id":5876,"depth":1155,"text":5877},{"id":6058,"depth":1155,"text":6059},{"id":6680,"depth":1155,"text":6681},{"id":6844,"depth":1144,"text":6844},[903],"ISEE:贱狗，折磨自己吧！","md",null,{"slots":6888},{},{"text":177,"minutes":178,"time":179,"words":180},{"title":175,"description":6884},{"loc":174,"images":6892},[6893,6894,6895,6896,6897,6898,6899,6900,6901,6902,6903,6904,6905,6906,6907,6908,6909,6910,6911,6912,6913,6914,6915,6916,6917,6918,6919,6920,6921,6922,6923,6924,6925,6926,6927,6928,6929,6930,6931,6932],{"loc":990},{"loc":1490},{"loc":1502},{"loc":1768},{"loc":2047},{"loc":2273},{"loc":2316},{"loc":2332},{"loc":2350},{"loc":2369},{"loc":2453},{"loc":2540},{"loc":2550},{"loc":2563},{"loc":2661},{"loc":2903},{"loc":3278},{"loc":3283},{"loc":3309},{"loc":4040},{"loc":4178},{"loc":4225},{"loc":4238},{"loc":4386},{"loc":4893},{"loc":4901},{"loc":4909},{"loc":4922},{"loc":5095},{"loc":5100},{"loc":5319},{"loc":5329},{"loc":5339},{"loc":5601},{"loc":5613},{"loc":5868},{"loc":5898},{"loc":6074},{"loc":6519},{"loc":6860},[175,6934],"课程笔记","tech","-noi6ESdUwDVisWFDDikSgniUhR3YriUwCM8cqThPOA",[6938,6939],{"title":165,"path":164,"stem":163,"date":166,"type":6935,"children":-1},{"title":647,"path":646,"stem":645,"date":78,"type":6935,"children":-1},1789057271259]